Answer:
Q(0) = 0C, Q(1) = 264nC, Q(2) = 952C Q(3) = 2088nC, Q(4) = 3696C Q(5) = 5800nC
Explanation:
I = 4t³ + 200t² + 60t
But charge of an object =》 Q = IT
Charge of an object is the product of the current and the time in which the current passes through the membrane.
When t = 0
Q = 4(0)³ + 200(0)² + 60(0) = 0C
When t = 1
Q = 4(1)³ + 200(1)² + 60(1) = 264nC
When t = 2
Q = 4(2)³ + 200(2)² + 60(2) = 952nC
When t= 3
Q = 4(3)³ + 200(3)² + 60(3) = 2088nC
When t= 4
Q = 4(4)³ + 200(4)² + 60(4) = 3696nC
When t = 5
Q = 4(5)³ + 200(5)² + 60(5) = 5800nC
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