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romanna [79]
3 years ago
8

As many points as I can give and a brainliest and a new friend, please help me!!!

Mathematics
1 answer:
lisabon 2012 [21]3 years ago
6 0

See the attached picture.

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Describing transformations<br> pls help!! will mark u
Anettt [7]

***********************************************************************

: Answer Moderated_Pasted From restricted website:

- Brainly Moniters:

4 0
3 years ago
Farmer Ted bales large round bales of hay to store in his barn for winter feeding. How much hay is in a round bale, in terms of
NNADVOKAT [17]

Answer:

20π ft³

Step-by-step explanation:

I just did it on the USATestprep

8 0
3 years ago
Solve for x: 10x – 3 + x &lt; 30
Gala2k [10]

Answer:

The correct answer would be the last one; x < 3.

Step-by-step explanation:

Step 1: Simplify both sides of the inequality.

11x - 3 < 30

Step 2: Add 3 to both sides.

11x - 3 + 3 < 30 + 3

11x < 33

Step 3L Divide both sides by 11.

11x/11 < 33/11

Therefor, the correct answer would be the last one: x < 3

Hope this helps!

7 0
3 years ago
Read 2 more answers
PLS HELP ASAP. QUESTION IN PICTURE
Anuta_ua [19.1K]

Answer: 50 degrees

Step-by-step explanation:

This is actually quite simple using the exterior angle theory

"The exterior angle theorem states that the measure of an exterior angle is equal to the sum of the measures of the two remote interior angles of the triangle"

In this case the exterior angle is 120 degrees, basically what the theorem states is that it the angle that you see outside the triangle equals the angle measurements of the 2 angles opposite of it, so just create an equation because you know 2 of the variables

120=70+x

120-70=x

Angle x = 50 degrees

4 0
2 years ago
Find the moment of inertia about the y-axis of the thin semicirular region of constant density
arlik [135]

The moment of inertia about the y-axis of the thin semicircular region of constant density is given below.

\rm I_y = \dfrac{1}{8} \times \pi r^4

<h3>What is rotational inertia?</h3>

Any item that can be turned has rotational inertia as a quality. It's a scalar value that indicates how complex it is to adjust an object's rotational velocity around a certain axis.

Then the moment of inertia about the y-axis of the thin semicircular region of constant density will be

\rm I_x = \int y^2 dA\\\\I_y = \int x^2 dA

x = r cos θ

y = r sin θ

dA = r dr dθ

Then the moment of inertia about the x-axis will be

\rm I_x = \int _0^r \int _0^{\pi}  (r\sin \theta )^2  \ r \  dr \  d\theta\\\\\rm I_x = \int _0^r \int _0^{\pi}  r^3 \sin ^2\theta  \  dr \  d\theta

On integration, we have

\rm I_x = \dfrac{1}{8} \times \pi r^4

Then the moment of inertia about the y-axis will be

\rm I_y = \int _0^r \int _0^{\pi}  (r\cos\theta )^2  \ r \  dr \  d\theta\\\\\rm I_y = \int _0^r \int _0^{\pi}  r^3 \cos ^2\theta  \  dr \  d\theta

On integration, we have

\rm I_y = \dfrac{1}{8} \times \pi r^4

Then the moment of inertia about O will be

\rm I_o = I_x + I_y\\\\I_o = \dfrac{1}{8} \times \pi r^4 + \dfrac{1}{8} \times \pi r^4\\\\I_o = \dfrac{1}{4} \times \pi r^4

More about the rotational inertia link is given below.

brainly.com/question/22513079

#SPJ4

3 0
2 years ago
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