By Pythagorean theorem we find that the length of the hypotenuse is 
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<h3>How to find the length of the hypotenuse</h3>
In the image attached we have a <em>right</em> triangle with two legs of <em>same</em> length. The hypotenuse of <em>right</em> triangles can be found by Pythagorean theorem, whose form is:
, where l is the length of the legs.
By Pythagorean theorem we find that the length of the hypotenuse is .
To learn more on Pythagorean theorem: brainly.com/question/26183488
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Step-by-step explanation:
5. 6x-8=9x+4
6x - 9x = 4+8
-3x = 12
x = -4
check, 6(-4) - 8=9(-4) + 4
-24-8 = -36+4
-32 = -32
6. 5a - 10 = 9a - 6
5a-9a = -6+10
-4a = 4
a = -1
check, 5(-1) -10 = 9(-1) -6
-5-10 = -9-6
-15 = -15
7. 8m-24 = 9-3m
8m + 3m = 9+24
11m = 33
m = 3
check, 8(3)-24 = 9- 3(3)
24-24 = 9-9
0 = 0
8. 10- 3z = z + 30
10-30 = z +3z
-20=4z
-5 = z
check, 10 - 3(-5) = (-5)+30
10+15 = 25
25=25
9. 3k - 14 = 10 +5k
3k - 5k = 10+14
-2k = 24
k = -12
check, 3(-12)-14 = 10+5(-12)
-36-14 = 10-60
-50 = -50
10. 6c + 8 = 2c -16
6c - 2c = -16-8
4c = -24
c = -6
check, 6(-6)+8 = 2(-6) - 16
-36 + 8 = -12 - 16
-28 = -28
Let any integer be represented by x.
Then, the consecutive integer (the number that follows) should be x+1.
The statement wants us to prove;
(x+1)²-x²=x+(x+1) <-- solve left hand side
x²+x+x+1²-x²
2x+1 (solution for left hand side)
Now solve for right hand side.
x+(x+1)= 2x+1
As noticed, the LHS=RHS (left hand side= right hand side), therefore, the difference of squared consecutive numbers subtracted is equal to the sum of the two integers.
Hope I helped :)
Answer: 17.320508075689
Step-by-step explanation:
