The sum of three consecutive odd integers is 76 less then seven times the middle number. The three integers are 17, 19 and 21 respeectively
<h3><u>Solution:</u></h3>
Since each consecutive odd integer is separated by a difference of 2
Let "n" be the first integer
n + 2 be the second integer
n + 4 be the third integer
Given that the sum of three consecutive odd integers is 76 less then seven times the middle number
Which means,
The sum of ( n, n + 2, n + 4) is equal to 76 less than seven times the middle number ( 7(n + 2))
That is,
n + n + 2 + n + 4 = 7(n + 2) - 76
3n + 6 = 7n + 14 - 76
4n = 68
n = 17
So we get:
First integer = n = 17
Second integer = n + 2 = 17 + 2 = 19
Third integer = n + 4 = 17 + 4 = 21
Thus the three consecutive odd integers are 17, 19 and 21 respeectively
Answer:
180
Step-by-step explanation:
Each is 60. 60*3 = 180 Degrees
Answer:
x = 4
Step-by-step explanation:
Simplifying
3x + 15 = 6x + 3
Reorder the terms:
15 + 3x = 6x + 3
Reorder the terms:
15 + 3x = 3 + 6x
Solving
15 + 3x = 3 + 6x
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-6x' to each side of the equation.
15 + 3x + -6x = 3 + 6x + -6x
Combine like terms: 3x + -6x = -3x
15 + -3x = 3 + 6x + -6x
Combine like terms: 6x + -6x = 0
15 + -3x = 3 + 0
15 + -3x = 3
Add '-15' to each side of the equation.
15 + -15 + -3x = 3 + -15
Combine like terms: 15 + -15 = 0
0 + -3x = 3 + -15
-3x = 3 + -15
Combine like terms: 3 + -15 = -12
-3x = -12
Divide each side by '-3'.
x = 4
Simplifying
x = 4
