Answer:
The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).
Step-by-step explanation:
The (1 - <em>α</em>)% confidence interval for the difference between population means is:

The information provided is as follows:

The critical value of <em>z</em> for 98% confidence level is,

Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:


Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).
Answer:
50d * 0.35m
Step-by-step explanation:
so I don't normally do it like this it would normally be 50 * 0.35x. but the days also had a fee unless she doesn't have it for 2 days and only has it one but d is the days she has it and m is the miles driven the * is times
you would have to find out the days she has it unless you don't have that is would be the answer above (if I am wrong I'm sorry)
Answer:
4 miles
Step-by-step explanation:
Let
x ----> the time to returned back biking in hours
d ---> the distance in miles
s ---> speed in miles per hour
Remember that
The speed or rate is equal to divide the distance by the time

The distance is equal to multiply the speed by the time

we know that

The distance to his friend's house and the distance of return is the same
so

solve for x

subtract 4x both sides



The total distance of the round trip is

substitute the value of x


Answer:-10
Step-by-step explanation:
45 +5=-5x
-5x=50
X=-10