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n200080 [17]
3 years ago
8

6y+4−3y−7=3(y−1) How many solutions are for this?

Mathematics
2 answers:
Kryger [21]3 years ago
8 0

Answer:

Infinite amount of solutions.

General Formulas and Concepts:

  • Order of Operations: BPEMDAS
  • Regular + Equality Properties

Step-by-step explanation:

<u>Step 1: Define equation</u>

6y + 4 - 3y - 7 = 3(y - 1)

<u>Step 2: Solve for </u><em><u>y</u></em>

  1. Combine like terms:                         3y - 3 = 3(y - 1)
  2. Distribute 3:                                       3y - 3 = 3y - 3
  3. Subtract 3y on both sides:               -3 = -3

Here we see that there will be infinite amount of solutions. We can plug in any number <em>y</em> and it will render the equation true.

baherus [9]3 years ago
7 0

No solutions.

General Formulas and Concepts:

Order of Operations: BPEMDAS

Regular + Equality Properties

Step-by-step explanation:

Step 1: Define equation

6y + 4 - 3y - 7 = 3(y - 1)

Step 2: Solve for y

Combine like terms:                         3y - 3 = 3(y - 1)

Distribute 3:                                       3y - 3 = 3y - 1

Subtract 3y on both sides:               -3 ≠ -1

Here we see that there will be no solutions of y.

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Learn more:

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Answer:

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Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 553, \sigma = 72

If the board wants to set the passing score so that only the best 10% of all applicants pass, what is the passing score?

This is the value of X when Z has a pvalue of 1-0.1 = 0.9. So it is X when Z = 1.28.

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