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n200080 [17]
2 years ago
8

6y+4−3y−7=3(y−1) How many solutions are for this?

Mathematics
2 answers:
Kryger [21]2 years ago
8 0

Answer:

Infinite amount of solutions.

General Formulas and Concepts:

  • Order of Operations: BPEMDAS
  • Regular + Equality Properties

Step-by-step explanation:

<u>Step 1: Define equation</u>

6y + 4 - 3y - 7 = 3(y - 1)

<u>Step 2: Solve for </u><em><u>y</u></em>

  1. Combine like terms:                         3y - 3 = 3(y - 1)
  2. Distribute 3:                                       3y - 3 = 3y - 3
  3. Subtract 3y on both sides:               -3 = -3

Here we see that there will be infinite amount of solutions. We can plug in any number <em>y</em> and it will render the equation true.

baherus [9]2 years ago
7 0

No solutions.

General Formulas and Concepts:

Order of Operations: BPEMDAS

Regular + Equality Properties

Step-by-step explanation:

Step 1: Define equation

6y + 4 - 3y - 7 = 3(y - 1)

Step 2: Solve for y

Combine like terms:                         3y - 3 = 3(y - 1)

Distribute 3:                                       3y - 3 = 3y - 1

Subtract 3y on both sides:               -3 ≠ -1

Here we see that there will be no solutions of y.

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