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Inessa [10]
4 years ago
9

Graph the rational function f (x)=- 3x + 1 -x+2

Mathematics
2 answers:
ruslelena [56]4 years ago
7 0
Y=3 seems the best out of this
Nataly_w [17]4 years ago
6 0

Answer:

Step-by-step explanation:

You must show that this is a rational function.  As written, it is not such.

         -3x + 1

f(x) = ------------

           -x + 2

is a rational function; the horizontal line --------- indicates division.

If we let x grow large, the graph approaches the horizontal line y = 3, which we call "the horizontal asymptote."  There is a vertical asymptote at x = 2, which we know because the denominator will be zero at that x value.  The vertical intercept is

f(0) = 1/2, or (0, 1/2).

As x decreases towards negative infinity, the graph approaches the horizontal line (horizontal asymptote) y = 3.

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Each day of the work week, Mr. Harbin uses 34 of a gallon of gas. Which estimate best describes the amount of gas Mr. Harbin wou
valentinak56 [21]

D. because each day =34 and it is 5days 5×34= 170 so the answer is more than 4 gallons

3 0
3 years ago
Can someoneplzzz do this???<br> Domain:<br> Range
slava [35]

Greetings! Hope this helps!

Answer

D {-3, 5}

R: {0,4}

Have a good day!

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A brainliest would help tons! :D

3 0
3 years ago
A dog show has 6 small dogs, 12 medium-sized dogs, and 6 large dogs. What is the probability that a dog chosen at random is a sm
sineoko [7]

Answer:

6/24= 3/12 = 1/4= 25%

Step-by-step explanation:

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4 0
3 years ago
Determine the general solution of:<br><br> sin 3x - sin x = cos2x
SpyIntel [72]
Sin³ x-sin x=cos ² x

we know that:
sin²x + cos²x=1  ⇒cos²x=1-sin²x
Therefore:

sin³x-sin x=1-sin²x
sin³x+sin²x-sin x-1=0

sin³x=z

z³+z²-z-1=0

we divide by Ruffini method:
              1     1     -1     -1
        1           1      2      1                z=1
-------------------------------------
              1     2      1      0
       -1         -1      -1                       z=-1
--------------------------------------
              1     1       0                       z=-1

Therefore; the solutions are z=-1 and z=1

The solutions are:
if z=-1, then
sin x=-1   ⇒x= arcsin -1=π+2kπ    (180º+360ºK)   K∈Z


if z=1, then
sin x=1   ⇒ x=arcsin 1=π/2 + 2kπ   (90º+360ºK)   k∈Z

π/2 + 2kπ    U   π+2Kπ=π/2+kπ     k∈Z    ≈(90º+180ºK)

Answer: π/2 + Kπ    or     90º+180ºK          K∈Z
Z=...-3,-2,-1,0,1,2,3,4....
6 0
3 years ago
Natalie's team needs to make a decision on how to handle a big product recall. People on the team have a lot of strong opinions.
zheka24 [161]

Answer:

esta padre tu pregunta si que bueno

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3 years ago
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