After 12 months, Quynh will have saved $800
Simply follow the pattern shown on the graph.
Month 1: 250
Month 2: 300
Month 3: 350
Month 4: 400
Month 5: 450
Month 6: 500
Month 7: 550
Month 8: 600
Month 9: 650
Month 10: 700
Month 11: 750
Month 12: 800
81 is the answer to your question
Answer:
<h3>C.) The area of EFGH is always ¹/₂ of the area of the rectangle. </h3>
Step-by-step explanation:
If EG is parallel to the side of the rectangle then lenght of EG is equal to width of rectangle.
If F and H are midpoints of sides of rectangle then FH is parallel to the side of rectangle {wich is perpendicular to the side parallel to EG}. That means the lenght of FH is equal to lenght of rectangle, and FH is perpendicular to EG.
Then FH is sum of hights of triangles EFG and EHG
, and the area of EFGH is sum of areas of triangles EFG and EHG
.
So the area of the rectangle: ![\bold{A_{rectangle}=EG\cdot FH}](https://tex.z-dn.net/?f=%5Cbold%7BA_%7Brectangle%7D%3DEG%5Ccdot%20FH%7D)
The area of the kite:
![A_{kite}=P_{_{\Delta EFG}}+P_{_{\Delta EHG}}\\\\A_{kite}=\frac12 EG\cdot H_{_{\Delta EFG}}+\frac12 EG\cdot H_{_{\Delta EHG}}\\\\ A_{kite}=\frac12 EG\cdot (H_{_{\Delta EFG}}+H_{_{\Delta EHG}})\\\\A_{kite}=\frac12 EG\cdot FH\\\\A_{kite}=\frac12 A_{rectangle}](https://tex.z-dn.net/?f=A_%7Bkite%7D%3DP_%7B_%7B%5CDelta%20EFG%7D%7D%2BP_%7B_%7B%5CDelta%20EHG%7D%7D%5C%5C%5C%5CA_%7Bkite%7D%3D%5Cfrac12%20EG%5Ccdot%20H_%7B_%7B%5CDelta%20EFG%7D%7D%2B%5Cfrac12%20EG%5Ccdot%20H_%7B_%7B%5CDelta%20EHG%7D%7D%5C%5C%5C%5C%20A_%7Bkite%7D%3D%5Cfrac12%20EG%5Ccdot%20%28H_%7B_%7B%5CDelta%20EFG%7D%7D%2BH_%7B_%7B%5CDelta%20EHG%7D%7D%29%5C%5C%5C%5CA_%7Bkite%7D%3D%5Cfrac12%20EG%5Ccdot%20FH%5C%5C%5C%5CA_%7Bkite%7D%3D%5Cfrac12%20A_%7Brectangle%7D)
No matter the height of the triangles, so no matter the location of the EG
Answer: 14 2/3in
Step-by-step explanation:
Answer:
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