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meriva
2 years ago
7

Triangle RST is made of points R(-10, 5.6), S(0, 7) and T(-6, -34).

Mathematics
1 answer:
vivado [14]2 years ago
4 0

Answer:R(-10, 5.6) => R'(10, -5.6)

S(0, 7) => S'(0, -7)

T(-6, -34) => T'(6, 34)

Step-by-step explanation:

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Examine the following equation and classify the type of solution.
Viktor [21]

Answer:

<h2>infinitely many solutions</h2>

Step-by-step explanation:

5x - 6 = 3x - 6 + 2x     <em>combine like terms</em>

5x - 6 = (3x + 2x) - 6

5x - 6 = 5x - 6         <em>subtract 5x from both sides</em>

-6 = -6        TRUE

Therefore the equation has infinitely many solutions.

5 0
3 years ago
Help I will give all the good stuff to you if you help me!
Law Incorporation [45]

Answer:

I think it is triangle, pentagon, heptagon, decagon

5 0
3 years ago
An elementary school class ran 1 mile in an average of 11 minutes with a standard deviation of 3 minutes. Rachel, a student in t
EleoNora [17]

Answer:

Rachel

Step-by-step explanation:

We need to measure how far (towards the left) are the students from the mean in<em> “standard deviations units”</em>.  

That is to say, if t is the time the student ran the mile and s is the standard deviation of the class, we must find an x such that

mean - x*s = t

For Rachel we have

11 - x*3 = 8, so x = 1.  

Rachel is <em>1 standard deviation far (to the left) from the mean</em> of her class

For Kenji we have

9 - x*2 = 8.5, so x = 0.25

Kenji is <em>0.25 standard deviations far (to the left) from the mean</em> of his class

For Nedda we have

7 - x*4 = 8, so x = 0.25

Nedda is also 0.25 standard deviations far (to the left) from the mean of his class.

As Rachel is the farthest from the mean of her class in term of standard deviations, Rachel is the fastest runner with respect to her class.

8 0
3 years ago
What does n^9/n^5 equal
vovangra [49]

Answer:

n^4

Step-by-step explanation:

Rule:

\dfrac{a^m}{a^n} = a^{m - n}

Your problem:

\dfrac{n^9}{n^5} = n^{9 - 5} = n^4

4 0
3 years ago
X=? Y=6<br> 75 degree angle at (0,0)<br> What is X?
choli [55]

Answer:

X=12-6\sqrt{3}=1.6077

Step-by-step explanation:

Given that Y=6

\tan(75)=\frac{Y}{X} \\X=\frac{Y}{\tan(75)}=Y\cot75=6\cot75 \\\\Calculate \ \cot(75)\\\tan(75)=\tan(45+30)=\frac{\tan45+\tan30}{1-\tan45 \cdot \tan30} =\frac{1+\frac{1}{\sqrt{3} } }{1-\frac{1}{\sqrt{3} } } \\\tan75=\frac{\sqrt{3}+1 }{\sqrt{3}-1 } =2+\sqrt{3} \\\cot75=\frac{1}{2+\sqrt{3} } =\frac{2-\sqrt{3} }{2^2-3} =2-\sqrt{3} \\\\Hence\\X=6\cot75=6 \cdot(2-\sqrt{3})\\X=12-6\sqrt{3} \approx1.6077

5 0
3 years ago
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