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kherson [118]
3 years ago
9

HELPPP I DONT KNOW IF ITS CORRECT MAYBE WILL GIVE BRAINLEST

Mathematics
2 answers:
algol133 years ago
3 0
-2.5 and -4.5 go in the left box because they are less than -2. -.5 and .5 go in the middle box because they are greater than-2 but less than 1. 1.5 and 4 go in the right box because they are greater than 1
Paha777 [63]3 years ago
3 0
-2.5 and -4.5 go in the “Below -2” box
-0.5 and 0.5 go in the “Between -2 and 1” box
1.5 and 4 go in the “Above 1” box
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16.437 rounded to the nearest tenths is
Akimi4 [234]

Answer:

16

Step-by-step explanation:

8 0
2 years ago
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5. Solve the equation. 8/x+3 = 1/x+1
Helga [31]

Answer:

x = -5/7

Step-by-step explanation:

8               1

---------- = ----------

x+3           x+1

Using cross products

8 (x+1) = 1 (x+3)

Distribute

8x+8 = x+3

Subtract x from each side

8x-x +8 = x-x+3

7x+8 =3

Subtract 8 from each side

7x +8-8 =3-8

7x = -5

Divide each side by 7

7x/7 = -5/7

x = -5/7

4 0
3 years ago
A washer and dryer cost $989 combined. The washer costs $89 more then the dryer. What is the cost of the dryer?
Stells [14]

Answer The washer costs $539.  The dryer cost $450

Step-by-step explanation:

7 0
2 years ago
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A rare form of malignant tumor occurs in 11 children in a​ million, so its probability is 0.000011. Four cases of this tumor occ
Shkiper50 [21]

Answer:

a) The mean number of cases is 0.14608 cases.

b) The probability that the number of cases is exactly 0 or 1 is 0.990.

c) The probability of more than one case is 0.010

d) No, because the probability of more than one case is very small

Step-by-step explanation:

We can model this problem with a Poisson distribution, with parameter:

\lambda=r*t=0.000011*13,280=0.14608

a) The mean amount of cases is equal to the parameter λ=0.14608.

b) The probability of having 0 or 1 cases is:

P(k=0)=\frac{\lambda^0 e^{-\lambda}}{0!}=\frac{1*0.864}{1} =0.864\\\\ P(k=1)=\frac{\lambda^1 e^{-\lambda}}{0!}=\frac{0.14608*0.864}{1} =0.126\\\\P(k\leq1)=0.864+0.126=0.990

c) The probability of more than one case is:

P(k>1)=1-P(k\leq 1)=1-0.990=0.010

d) The cluster of 4 cases can not be due to pure chance, as it is a very high proportion of cases according to the average rate. Just having more than one case has a probability of 1%.

7 0
3 years ago
A. Show that the vector v = ai + bj is perpendicular to the line ax + by = c by establishing that the slope of v is the negative
pishuonlain [190]

Answer:

Part A:

m_1m_2=-1

\frac{b}{a}(\frac{-a}{b})=-1\\-1=-1

Hence proved that Vector= ai + bj is perpendicular to the line ax + by = c.

Part B:

Slope of vector = \frac{b}{a}

Step-by-step explanation:

Condition for perpendicular is:

m_1m_2=-1

Part A:

Consider the vector v = ai + bj

x component of vector=a

y component of vector=b

Slope of vector=m_1=\frac{y}{x}=\frac{b}{a}

Consider the line ax + by = c:

Rearranging the equation:

ax+by=c

by=c-ax

y=\frac{-ax}{b}+\frac{c}{b}

According to general equation of line: y=mx+c

Where m is the slope

In our case the slope of above line is:

m_2=\frac{-a}{b}

According to the condition of perpendicular:

m_1m_2=-1

\frac{b}{a}(\frac{-a}{b})=-1\\-1=-1

Hence proved that Vector= ai + bj is perpendicular to the line ax + by = c.

Part B:

Slope of vector is also calculated above.

Since the slope of vector is negative reciprocal of the slope of the given line:

According to equation of line ax + by = c

y=\frac{-ax}{b}+\frac{c}{b}

According to  general equation of line: y=mx+c

Where m is the slope

Slope of given line=m=\frac{-a}{b}

negative reciprocal of the slope of the given line = \frac{b}{a}

Slope of vector = \frac{b}{a}

5 0
2 years ago
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