Answer:
It will take 6 hours for the new pump to drain the pool.
Step-by-step explanation:
As the complete question is not given, the complete question is found online and is attached herewith
Let the rate of new pump is given as x=W/t_1
Let the rate of the old pump is given as y=W/t_2
it is given that the time t_2=2t_1
So by substituting the values of t_2 in the rate equation of y
y=W/2t_1
y=(W/t_1*2)=x/2
Also the total rate of both the pumps is given as W/t3 where t3 is given as 4 hours so the equation becomes
x+y=W/4
x+x/2=W/4
3x/2=W/4
As x=W/t_1
3W/2t_1=W/4
Now as W is same on both sides so
3/2t_1=1/4
12=2t_1
t_1=6 hours
So it will take 6 hours for the new pump to drain the pool.
N-10=32
add 10 to both sides
n-10+10=32+10
-10+10=0
n=42
Answer:
Jug B can hold 2340 ml.
Step-by-step explanation:
Given
The amount in Jug A = 1800ml
To determine
How much does jug B hold?
Give that the Jug B holds 3/10 more, i.e.

Thus,
The total amount in Jug B = 540+1800
= 2340 ml
Therefore, Jug B can hold 2340 ml.
Answer:
84
Step-by-step explanation:
7 Sizes * 3 Lengths * 4 Colors = 84