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seropon [69]
3 years ago
14

Solve for f(5): f(5) = -x + 4

Mathematics
1 answer:
MariettaO [177]3 years ago
3 0

Answer: look at the picture

Step-by-step explanation: hope this help

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1. Charlene wants to center a rectangular pool in her backyard so that the edges of the pool are an equal distance from the edge
Inga [223]

First, we have to calculate the length of the sides of the pool, we are told that the scale factor of the backyard to the pool size equals 1/2, then we can find the length of the sides of the pool by multiplying the lengths of the sides of the backyard by 1/2, like this:

length of the pool = length of the yard * 1/2

width of the pool = width of the yard * 1/2

By replacing the 60 m for the length of the yard and 50 m for the width, we get:

length of the pool = 60 * 1/2 = 30

width of the pool = 50 * 1/2 = 25

Let's call x1 to the distance from the base of the pool to the bottom side of the yard and x2 to the distance from the top side of the pool to the top side of the yard, then we can formulate the following equation:

width of the yard = width of the pool + x1 + x2

Since we want the edges to be at an equal distance, x1 and x2 are the same, then we can rewrite them as x:

width of the yard = width of the pool + x + x

width of the yard = width of the pool + 2x

Replacing the known values:

60 = 30 + 2x

From this equation, we can solve for x to get:

60 - 30 = 30 - 30 + 2x

30 = 2x

30/2 = 2x/2

15 = x

x = 15

Now, let's call y1 to the distance from the right side of the corresponding side of the yard and y2 to the distance from the left side of the pool to the left side of the yard, with this, we can formulate the following equation:

length of the yard = length of the pool + y1 + y2

Since we want the edges to be at an equal distance, y1 and y2 are the same, then we can rewrite them as y:

length of the yard = length of the pool + y + y

length of the yard = length of the pool + 2y

Replacing the known values:

50 = 25 + 2y

50 - 25 = 25 - 25 + 2y

25 = 2y

25/2 = 2y/2

12.5 = y

y = 12.5

Now, we know that the pool must be at a distance of 15 m from the horizontal sides of the pool to the horizontal sides of the yard and that it must be at a distance of 12.5 m from the vertical sides of the pool to the vertical sides of the yards.

Here is a figure that depicts the results:

5 0
1 year ago
What is the answer to 3b+b+6
AysviL [449]
Add all the like terms

3b + b = b(3 + 1) = 4b

So, 3b + b + 6 = 4b + 6
7 0
3 years ago
Read 2 more answers
(-8, 4), (4, -4)<br> Write in standard form
Serjik [45]

Answer written in standard form:

2x + 3y = -4

7 0
3 years ago
Read 2 more answers
A rectangle and square have the same area.
olganol [36]

Answer:

12x*3x=36x^2

squarelength=\sqrt{36x^2}=6x

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Answer for 2,3,4 help pls thanks
Lemur [1.5K]

(90 \times 15) \div 9 =  \: is \: your \: answer

Step-by-step explanation:

1. B is true

2 . I don't know

3.

4 0
3 years ago
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