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rewona [7]
3 years ago
7

One member of a gardening club can plant flowers in 12 hours. With two members of the club working together the job can be done

in 8 hours. How long would it take the second member of the club , working alone to do the job
Mathematics
1 answer:
mariarad [96]3 years ago
4 0

Answer:

24 hours

Step-by-step explanation:

One member of the gardening club can alone plant flowers in 12 hours.

So in 1 hour he can plant 1/12 of the flowers.

Let the time required by the second member of the club to plant flowers alone be x hours.

Then in 1 hour he can plant 1/x of the flowers.

Now when the two members work together,each hour they can plant:

\[\frac{1}{12}+\frac{1}{x}\] of the flowers.

But they can together complete the job in 8 hours. So in one hour they plant 1/8 of the flowers.

=> \[\frac{1}{12}+\frac{1}{x}=\frac{1}{8}\]

=> \[\frac{1}{x}=\frac{1}{24}\]


=> x=24

So the second member can plant the flowers alone in 24 hours

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               4a = (2, 3.5)             4b = (2, 3)           4c = (2, 5.375)

<u>Step-by-step explanation:</u>

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3d)\quad 6\bigg(\dfrac{3}{5}\bigg)\quad =\dfrac{18}{5}\qquad \qquad A(-2, 1) +(3.6,0)= C(1.6,1)

***********************************************************************************

The length of AB is 5 and is vertical (affects the y-coordinate)

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