He is a victim of plagiarism.
Plagiarism is when someone steals someone else's work, to help benefit themselves. Taking credit for the other person work.
Hope this helps!
Answer:Fraud detection through analytical method is used for detection of the fraud transactions,bribe activity etc in companies, business,etc. This techniques helps in the reduction of financial frauds in the organization, have the control over company to protect it,decrease in the fraud associated costs etc.
It has the capability of identifying the fraud which has happened or going to happen through the analytical ways and human interference. The organizations or companies require efficient processing and detection system for identification of such false happening.
Technology helps business professionals, keep more organized, communicate better, and effectively keeps businesses secure. Technology helps keep employee information and business paper work more organized using computers and software; while making it easier to communicate with employee's using e-mail and memo's.
if wrong sry :(
I don't know if this is on your list, but I know for a fact that the Nintendo 64 system (or N64) has a 64-bit architecture.
Answer:
See explaination for the program code
Explanation:
The code below
Pseudo-code:
//each item ai is used at most once
isSubsetSum(A[],n,t)//takes array of items of size n, and sum t
{
boolean subset[n+1][t+1];//creating a boolean mtraix
for i=1 to n+1
subset[i][1] = true; //initially setting all first column values as true
for i = 2 to t+1
subset[1][i] = false; //initialy setting all first row values as false
for i=2 to n
{
for j=2 to t
{
if(j<A[i-1])
subset[i][j] = subset[i-1][j];
if (j >= A[i-1])
subset[i][j] = subset[i-1][j] ||
subset[i - 1][j-set[i-1]];
}
}
//returns true if there is a subset with given sum t
//other wise returns false
return subset[n][t];
}
Recurrence relation:
T(n) =T(n-1)+ t//here t is runtime of inner loop, and innner loop will run n times
T(1)=1
solving recurrence:
T(n)=T(n-1)+t
T(n)=T(n-2)+t+t
T(n)=T(n-2)+2t
T(n)=T(n-3)+3t
,,
,
T(n)=T(n-n-1)+(n-1)t
T(n)=T(1)+(n-1)t
T(n)=1+(n-1)t = O(nt)
//so complexity is :O(nt)//where n is number of element, t is given sum