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Doss [256]
3 years ago
9

you are the manager of a virtual team that is working on a project. You uploaded a Word document to an OneDrive account that you

r team is sharing. The document has been modified five times since uploading it and the contents have gone off on a tangent. You want the original document. How can you do this?​
Computers and Technology
1 answer:
Valentin [98]3 years ago
6 0

He can simply right click on the file and select restore previous versions. Instead of the manager choosing to recreate the Word document from scratch, he can recover the initial and previous version of the file. Once he has clicked the “Restore previous versions” option, a list of available items will pop. He will click the version he would like restored and click “Restore”

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Explanation:

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A ______ or workstation computer is typically used by one or a small number of people to perform everyday productivity tasks, su
sveta [45]

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Explanation:

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4 years ago
Define horizontal scroll bar​
Murrr4er [49]

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2 years ago
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A television advertisement claiming that a product is "light-years ahead of its time" does not make sense because (a) it doesn’t
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Answer:

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5 0
4 years ago
Write a test client for Randomthat checks that two methods, namely, nextGaussian()and nextLong()in the library operate as expect
xenn [34]

Answer:

/ TestRandom.java

import java.util.Random;

public class TestRandom {

   // method to find the mean value of set of numbers

   // using Number as data type, so that it can represent both Double and Long

   // types needed for this program

   static double calculateMean(Number array[]) {

        double sum = 0;

        // summing values

        for (int i = 0; i < array.length; i++) {

            sum += array[i].doubleValue();

        }

        // finding average and returning it

        double avg = (double) sum / array.length;

        return avg;

   }

   // method to find the standard deviation value of set of numbers

   // using Number as data type, so that it can represent both Double and Long

   // types needed for this program

   static double calculateSD(Number array[], double mean) {

        // initializing sum of squared difference between each number and mean

        // to 0

        double sumSquaredDiff = 0;

        // looping

        for (int i = 0; i < array.length; i++) {

            // finding difference between current number and mean, squaring the

            // result, adding to sumSquaredDiff

            sumSquaredDiff += Math.pow(array[i].doubleValue() - mean, 2);

        }

        // finding variance

        double variance = (double) sumSquaredDiff / array.length;

        // finding square root of variance as standard deviation

        double sd = Math.sqrt(variance);

        return sd;

   }

   public static void main(String[] args) {

        // if no command line arguments given, displaying usage and quit

        if (args.length == 0) {

            System.out.println("Usage: java TestRandom <n>");

            System.exit(0);

        }

        // parsing first argument as integer N

        int N = Integer.parseInt(args[0]);

        // declaring a Double array and a Long array of size N

        Double gaussian[] = new Double[N];

        Long lng[] = new Long[N];

        // Random number generator

        Random random = new Random();

        // looping for N times

        for (int i = 0; i < N; i++) {

            // generating a guassian number, adding to array

            gaussian[i] = random.nextGaussian();

            // generating a long number, adding to array

            lng[i] = random.nextLong();

        }

        // finding average and standard deviation of both array values, we can

        // use the same functions for both types

        double avgGaussian = calculateMean(gaussian);

        double sdGaussian = calculateSD(gaussian, avgGaussian);

        double avgLong = calculateMean(lng);

        double sdLong = calculateSD(lng, avgLong);

        // displaying mean and standard deviation of both, formatted to 2 digits

        // after decimal point. the gaussian values will yeild a mean value

        // close to 0 and a standard deviation close to 1

        System.out.printf("Mean of %d gaussian values: %.2f\n", N, avgGaussian);

        System.out.printf("Standard deviation: %.2f\n", sdGaussian);

        System.out.printf("Mean of %d long values: %.2f\n", N, avgLong);

        System.out.printf("Standard deviation: %.2f\n", sdLong);

   }

}

Explanation:

5 0
4 years ago
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