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grigory [225]
3 years ago
13

A two-runway (one runway for landing, one runway for taking off) airport is being designed for propeller-driven aircraft. The ti

me to land an airplane is known to be exponentially distributed, with a mean of 1.5 minutes. If airplane arrivals are assumed to occur at random, what arrival rate can be tolerated if the average wait in the sky is not to exceed 3 minutes? (Hint: A single landing strip airport is modeled by an M/M/1 queue.)
Mathematics
1 answer:
Nata [24]3 years ago
5 0

Answer:

\frac{4}{9}

Step-by-step explanation:

First, we gather the data:

The model is a single M/M/1 landing strip with \mu = \frac{2}{3}

This based on the assumption that service times are exponential.

Then, we must find the maximum rate such that w_{q} \leq 3

Using the M/M/1 table, we find that:

w_{p}  = \frac{\rho }{(\mu (1 -\rho)  } \\ \frac{\lambda }{\mu (1 - \lambda  } \leq 3

if and only if

\lambda\leq \frac{3\mu ^{2} }{(1 + 3\mu) }

=\frac{4}{9}

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Please help! I will mark as brainliest IF answer is right. <3
trasher [3.6K]

Solution

write the division as a fraction = 12y^4-4y^3 - 6y^2 + 36y - 22 over y-3 multiplied by r over y-3

r ×(2y^4 - 4y^3- 16y^2 + 36y- 22) over (y-3)^2

2ry^4 - 4ry^3 - 16ry^2 + 36ry - 22r over (y-3)^2

5 0
2 years ago
NEED HELP ASP
Nostrana [21]
<h3>Answer: B) $878.28</h3>

================================================

Explanation:

She starts off $16.75 in debt

Later on she deposits $16.75 to get completely out of debt and make the balance 0. This is after depositing the $5.72

So far her balance is $5.72

Add on $872.56 to get 5.72+872.56 = 878.28

-------------

This is what your steps may look like

-16.75 + (5.72 + 16.75)

-16.75 + (16.75 + 5.72)

(-16.75+16.75) + 5.72

(0) + 5.72

5.72

5.72+872.56

878.28

3 0
3 years ago
Read 2 more answers
A football quarterback enjoys practicing his long passes over 40 yards. He misses the first pass 40% of the time. When he misses
dangina [55]

Answer:

8% or 0.08

Step-by-step explanation:

Probability of missing the first pass = 40% = 0.40

Probability of missing the second pass = 20% = 0.20

We have to find the probability that he misses both the passes. Since the two passes are independent of each other, the probability that he misses two passes will be:

Probability of missing 1st pass x Probability of missing 2nd pass

i.e.

Probability of missing two passes in a row = 0.40 x 0.20 = 0.08 = 8%

Thus, there is 8% probability that he misses two passes in a row.

5 0
3 years ago
Read 2 more answers
Find the greater common factor of 10 and 24
son4ous [18]
The factors and prime factorization of 10 and 24. The biggest common factor number is the GCF number. So the greatest common factor 10 and 24 is 2.
3 0
3 years ago
Read 2 more answers
A restaurant earns $1073 on Friday and $1108 on Saturday. Write and solve an equation to find the amount xx (in dollars) the res
julia-pushkina [17]

Money earned by restaurant on Friday=$1073

Money earned by restaurant on Saturday=$1108

Let Money earned by restaurant on Sunday=$x

Average=$1000

\text { average}=\frac  { sum of all the observation}{total number of observation}

Number of observation=3

                           ⇒  3×  1000=1073+1108+x

                            ⇒3000=     2 181+x

                              ⇒3000-2181=x

                            ⇒x=819

The restaurant needs to earn on Sunday to average $1000 per day over the three-day period=$819


6 0
3 years ago
Read 2 more answers
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