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jenyasd209 [6]
3 years ago
6

If

alt="(5x-2)^2= ax^2 - bx +c" align="absmiddle" class="latex-formula">, what is the value of a+c^2?
Mathematics
2 answers:
love history [14]3 years ago
8 0

Answer:

41

Step-by-step explanation:

(5x - 2)² = ax² - bx + c

25x² - 20x + 4 = ax² - bx + c

a = 25

c = 4

a + c²

25 + 4²

25 + 16

41

lisov135 [29]3 years ago
6 0

Answer:

41

Step-by-step explanation:

(5x-2) ^2 = ax^2 -bx +c

Foil

(5x-2) (5x-2)

25x^2 -10x -10x +4

25x^2 -20x+4

a=25 b=20 c = 4

a+c^2 =25 +4^2 =25+16 = 41

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Answer:

  a  (3,-1)

Step-by-step explanation:

The number that "completes the square" is the square of half the x-coefficient, (-6/2)^2 = 9. Rearranging the given function to include the square trinomial, we have ...

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Comparing this to the generic vertex form ...

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2 years ago
Write a quadratic relation in the form y = ax2 + bx + c with roots 4 and - 3 and
pochemuha

Answer:

y =  2*x^2 - 2*x - 24

Step-by-step explanation:

If we have a quadratic function with roots a and b, we can write the equation for that function as:

y = f(x) = A*(x - a)*(x - b)

Where A is the leading coefficient.

In this case, we know that the roots are: 4 and -3

Then the function will be something like:

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Now we need to determine the value of A.

We also know that the graph of the function passes through the point (3, -12)

This means that:

f(3) = -12

Then:

-12 = A*(3 - 4)*(3 + 3)

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Then the equation is:

y = f(x) = 2*(x - 4)*(x + 3)

Now we need to write this in standard form, so we just need to expand the equation:

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y =  2*x^2 - 2*x - 24

4 0
2 years ago
Help please. this is really hard for me to understand.
bogdanovich [222]

Answer:

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8 0
3 years ago
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irinina [24]

Answer:

Step-by-step explanation:

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