If the 2nd term of a G.P series is 3/2 and the Fourth term is 3/8, find the first and common ratio of the series

Mathematics

1 answer:

V125BC [204]3 years ago

6 0

Step-by-step explanation:

second terms:

ar=3/2

forth term

ar^3=3/8

combine two equation:

r^2=1/4

r= +1/2 or -1/2

a=3 or -3

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2 years ago

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MrRissso [65]

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Now, If the exponent was negative like you asked....

$\left( \frac{27x^3}{8y^9}\right)^ {-\frac{5}{3}} \\\\\\ =\left( \frac{8y^9}{27x^3}\right)^ {\frac{5}{3}}\\\\\\ =\left( \frac{(2y^3)^3}{(3x)^3}\right)^ \frac{5}{3} \\\\\\ = \frac{(2y^3)^{3 \times \frac{5}{3} }}{(3x)^{3 \times \frac{5}{3} }} \\\\\\ =\frac{(2y^3)^{5 }}{(3x)^5} \\\\\\ =\frac{32y^{15}}{243x^5}$

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