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Eddi Din [679]
4 years ago
15

Will someone tell me if these are right ASAP

Mathematics
1 answer:
daser333 [38]4 years ago
7 0

Answer:

Select all except the first.

That would be:

  • both pairs of opposite sides are parallel.
  • both pairs of opposite sides are congruent.
  • one pair of opposite sides is both congruent and parallel.
  • that the diagonals bisect each other.

Step-by-step explanation:

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hodyreva [135]

199 *0.05 = 9.95

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99.50 * 0.047 = 4.68

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8.95 * 0.072 = 0.64

14.27 * 0.068 = 0.97

544.38 * 0.042 = 22.86

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28.56 * 0.075 = 2.14

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6 0
3 years ago
Not sure how to do this. help please
morpeh [17]

Answer:

I think it's s

Step-by-step explanation:

I think it's set equation.

3 0
3 years ago
Show if the following expressions are equivalent
kvasek [131]
Anwser is B i took the test
8 0
3 years ago
What are my zeros (x^2 - 8x + 1)?
Pavel [41]

Answer:

x= 7.87298334621                          x=.12701665379

Step-by-step explanation:

This is in standard form so we have to factor this into

x^2-8x + 16 + 1 = 16

(x-4)^2 = 15

(x-4) = \sqrt{15\\}

x-4= ± 3.87298334621

x-4 = 3.87298334621                      x-4= -3.87298334621

x= 7.87298334621                          x=.12701665379

7 0
3 years ago
Which inequality below will have a dashed boundary line with a shaded area above its graph? A. 7x − y ≤ 3 B. x − y ≤ 4 C. 2x − 9
patriot [66]
<span>Dashed boundary line means there is no equal sign in the problem. That eliminated the first two. Shaded above means it is greater than...

Now turn your inequalities into y = mx + b form
 2x - 9y > 2 --- subtract 2x from both sides
-9y > -2x + 2 -- divide by -9...and change inequality sign
y < 2/9x - 2/9 this says y is less then.....we need greater then...this is not it

try the next one...
4x + 7y > 3 --- subtract 4x from both sides
7y > 4x + 3 -- divide by 7
y > 4/7x + 3/7
this says y is greater then...this is the one we want</span>

The answer to your question is D. I hope that this is the answer that you were looking for and it has helped you.
3 0
3 years ago
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