What is the rate 470 feet in <br> five years written as feet per <br> year?

What is the number nearest to 10000 which is exactly divisible by 3, 4, 5, 6, 7, and 8?.

Tems11 [23]

10080 is the number nearest to 10000 that is divisible by 3, 4, 5, 6, 7, and 8.

Divisibility is being able to divide a number evenly and result to a whole number. Divisibility rules are set of rules to test if one number is divisible by another without doing much computation.

#1: divisibility by 2

A number is divisible by 2 if its last digit is even.

# 2: divisibility by 3:

A number is divisible by 3 if the sum of its digits is divisible by 3.

# 3: divisibility by 4

A number is divisible by 4 if the number represented by its last two digits is divisible by 4.

#4: divisibility by 5

A number is divisible by 5 if its last digit is 0 or 5.

# 5: divisibility by 6

A number is divisible by 6 if it is divisible by both 2 and 3.

# 6: divisibility by 7

Double the last digit and subtract it from a number made by the other digits. The result must be divisible by 7.

#7: divisibility by 8

A number is divisible by 8 if the number represented by its last three digits is divisible by 8.

#8: divisibility by 9

A number is divisible by 9 if the sum of its digits is divisible by 9.

# 9: divisibility by 10

A number is divisible by 10 if its last digit or the digit in the ones place is 0.

To get the number nearest to 10000 that is divisible by 3, 4, 5, 6, 7, and 8, consider first the numbers that are divisible by 5(numbers ending in 5 or 0) and narrow it down to numbers ending in 0 since numbers ending in 5 is not divisible by 2, thus making it indivisible by 6.

The process goes on by narrowing the list by checking its divisibility by 3, 4, 7 and 8.

To know more about divisibility rules, visit brainly.com/question/9462805.

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7 0

1 year ago

What is one way that authors can come up with ideas for providing context for their readers?(1 point)

nataly862011 [7]

Answer:

Brainstorming i think

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Name/ Uid:1. In this problem, try to write the equations of the given surface in the specified coordinates.(a) Write an equation

Gemiola [76]

To find:

(a) Equation for the sphere of radius 5 centered at the origin in cylindrical coordinates

(b) Equation for a cylinder of radius 1 centered at the origin and running parallel to the z-axis in spherical coordinates

Solution:

(a) The equation of a sphere with center at (a, b, c) & having a radius 'p' is given in cartesian coordinates as:

$(x-a)^{2}+(y-b)^{2}+(z-c)^{2}=p^{2}$

Here, it is given that the center of the sphere is at origin, i.e., at (0,0,0) & radius of the sphere is 5. That is, here we have,

$a=b=c=0,p=5$

That is, the equation of the sphere in cartesian coordinates is,

$(x-0)^{2}+(y-0)^{2}+(z-0)^{2}=5^{2}$

$\Rightarrow x^{2}+y^{2}+z^{2}=25$

Now, the cylindrical coordinate system is represented by $(r, \theta,z)$

The relation between cartesian and cylindrical coordinates is given by,

$x=rcos\theta,y=rsin\theta,z=z$

$r^{2}=x^{2}+y^{2},tan\theta=\frac{y}{x},z=z$

Thus, the obtained equation of the sphere in cartesian coordinates can be rewritten in cylindrical coordinates as,

$r^{2}+z^{2}=25$

This is the required equation of the given sphere in cylindrical coordinates.

(b) A cylinder is defined by the circle that gives the top and bottom faces or alternatively, the cross section, & it's axis. A cylinder running parallel to the z-axis has an axis that is parallel to the z-axis. The equation of such a cylinder is given by the equation of the circle of cross-section with the assumption that a point in 3 dimension lying on the cylinder has 'x' & 'y' values satisfying the equation of the circle & that 'z' can be any value.

That is, in cartesian coordinates, the equation of a cylinder running parallel to the z-axis having radius 'p' with center at (a, b) is given by,

$(x-a)^{2}+(y-b)^{2}=p^{2}$

Here, it is given that the center is at origin & radius is 1. That is, here, we have, $a=b=0,p=1$ . Then the equation of the cylinder in cartesian coordinates is,

$x^{2}+y^{2}=1$

Now, the spherical coordinate system is represented by $(\rho,\theta,\phi)$

The relation between cartesian and spherical coordinates is given by,

$x=\rho sin\phi cos\theta,y=\rho sin\phi sin\theta, z= \rho cos\phi$

Thus, the equation of the cylinder can be rewritten in spherical coordinates as,

$(\rho sin\phi cos\theta)^{2}+(\rho sin\phi sin\theta)^{2}=1$

$\Rightarrow \rho^{2} sin^{2}\phi cos^{2}\theta+\rho^{2} sin^{2}\phi sin^{2}\theta=1$

$\Rightarrow \rho^{2} sin^{2}\phi (cos^{2}\theta+sin^{2}\theta)=1$

$\Rightarrow \rho^{2} sin^{2}\phi=1$ (As $sin^{2}\theta+cos^{2}\theta=1$ )

Note that $\rho$ represents the distance of a point from the origin, which is always positive. $\phi$ represents the angle made by the line segment joining the point with z-axis. The range of $\phi$ is given as $0\leq \phi\leq \pi$ . We know that in this range the sine function is positive. Thus, we can say that $sin\phi$ is always positive.