Answer:
<h2>
20π in</h2>
Step-by-step explanation:
Length of an arc is expressed as 
. Given;
The length of the minor arc SV is expressed as:
Hence, The length of the arc SV is 20π in
We have m(<CBO) = (1/2) · m(<CBE) = (1/2) · ( x + z );
In the same way, m(<BCO) = (1/2) ·( x + y);
m(<BOC) = 180 - [(1/2) · ( x + z ) + (1/2) ·( x + y)] = 180 - (1/2)· ( x + x + y + z );
But, x + y + z = 180;
Then, m(<BOC) = 180 - (1/2)·( x + 180 );
Finally, m(<BOC) = 90 - (1/2)·x;
So, m(<BOC) = 90 - (1/2)·m(<BAC).
The answer is C because the formula for a right triangle is a^2 +b^2=c^2
Answer:
532
Step-by-step explanation:
The score that represents the top 20% = A score = 80%
Z score for 80% percentile = 0.842
We solve using the z score formula
z = (x-μ)/σ, where
x is the raw score = ??
μ is the population mean = 490
and σ is the population standard deviation = 50
Hence:
0.842 = x - 490/50
Cross Multiply
0.842 × 50 = x - 490
x = 0.842 × 50 + 490
x = 42.1 + 490
x = 532.1
Approximately = 532
Therefore, the test score = 532
You can use cross-products to solve this problem. For instance, this expression would be written as 5(8)= 7(-x), or 40= -7x. What you'd do then is simplify the expression by dividing both sides of the equation by the coefficient of x, such that you'd isolate x and have the value of x.
