3 years ago

If f(x) = 2x+3 and g(x) = x^2 + 1, find f(g(3)).

Mathematics

1 answer:

Ilia_Sergeevich [38]3 years ago

3 0

Answer:

Step-by-step explanation:

g(3) = 3²+1 = 10

f(g(3)) = 2(10) + 3

= 23

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Find the solution of y = 5x - 4 for x = -6.

forsale [732]

Answer:

D (-6, -34)

Step-by-step explanation:

y = 5x - 4

Let x = -6

y = 5(-6) - 4

=-30 -4

= -34

x = -6, y= -34

6 0

4 years ago

Read 2 more answers

I need help, 15 points!

Ira Lisetskai [31]

Answer:

3(a + 5b + 7c) and 2x(2 + 5y + 11z)

Step-by-step explanation:

3a + 15b + 21c

3(a + 5b + 7c)

4x + 10xy + 22xz

2x(2 + 5y + 11z)

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3 years ago

When and how do you use logarithms to solve exponential equations? give an example of an exponential equation that does not requ

tatuchka [14]

$\bf 5^{x+3}=\cfrac{1}{125}\implies 5^{x+3}=\cfrac{1}{5^3}\implies 5^{x+3}=5^{-3}
\\\\\\
\textit{because the bases are the same, the exponents must also be the same}
\\\\\\
x+3=-3\implies \boxed{x=-6}\\\\
-------------------------------\\\\
3^x=4^{2x}\implies log(3^x)=log(4^{2x})\implies xlog(3)=(2x)log(4)
\\\\\\
\cfrac{x}{2x}=\cfrac{log(4)}{log(3)}\implies \cfrac{1}{x}=\cfrac{log(4)}{log(3)}\implies \cfrac{log(3)}{log(4)}=x\implies \boxed{0.79248125\approx x}$