Given lines a, b, and c, if a⊥b and c⊥b then a⊥c. True or false

Can anybody help me with this ?

BabaBlast [244]

Answer:

1st scenario: 163.3°

2nd scenario: 125.2°

3rd scenario: 142.3°

Step-by-step explanation:

1st scenario: angles 1 and 2 form a linear pair and add up to 180

2nd scenario: angles 1 and 4 are same-side interior and add up to 180

3rd scenario: angles 1 and 8 are corresponding and equal; if angle 7 is 37.7 then angle 8 is 142.3 (they form a linear pair). Since angles 1 and 8 are equal then angle 1 is also 142.3

6 0

3 years ago

Pls help me help me

grandymaker [24]

Answer:

C.

Step-by-step explanation:

When two lines are parallel, their slopes are the same.

Since the slope of line <em>l </em>is 2/7, the slope of its parallel line <em>m</em> must also be 2/7.

The answer is C.

3 0

3 years ago

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Evaluate \dfrac j4 4 j ? start fraction, j, divided by, 4, end fraction when j=12j=12j, equals, 12.

cricket20 [7]

We need to evaluate the value of fraction $\frac{j}{4}$ .

We also given j=12.

In order to evaluate the value of fraction $\frac{j}{4}$ , we need to plug j=12.

Plugging j=12, we get

$\frac{j}{4}= \frac{12}{4}$

We have 12 in numerator and 4 in denominator.

We always divide top number by bottom number.

So, we need to divide 12 by 4.

On dividing 12 by 4 we get 3.

<h3>Therefore, $\frac{j}{4} = 3.$ </h3>

3 0

3 years ago

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The Pacific halibut fishery has been modeled by the differential equation dy dt = ky 1 − y K where y(t) is the biomass (the tota

Dafna1 [17]

Answer:

a. The biomass weighs 2.30 * 10^7 kg after a year

b. It'll take 2.56 years to get to 4*10^7kg

Step-by-step explanation:

a.

k = 0.78,K = 6E7 kg

Given

dy/dt = ky(1- y/K)

Make ky dt the subject of formula

ky dt = dy/(1-y/K) --- make k dt the subject of formula

k dt = dy/(y(1-y/K))

k dt = K dy / y(K-y)

k dt = ((1/y) + (1/(K-y)))dy ---- integrate both sides

kt + c = ln(y/(K-y))

Ce^(kt) = y/(K-y)

Substitute the values of k and K

Ce^(0.78t) = y/(6*10^7 - y) ----- (1)

Given that y(0) = 2 * 10^7kg

(1) becomes

Ce^(0.78*0) = (2 * 10^7)/(6*10^7 - 2*10^7)

Ce° = (2*10^7)/(4*10^7

C = 2/7

Substitute 2/7 for C in (1)

2/7e^0.78t = y/(6*10^7 - y) ---(2)

We're to find the biomass a year later

So, t = 1

2/7e^0.78 = y/(6*10^7 - y)

0.62 = y/(6*10^7 - y)

y = 0.62(6*10^7 - y)

y = 0.62*6*10^7 - 0.62y

y + 0.62y = 0.62*6*10^7

1.62y = 0.62*6*10^7

1.62y = 3.72 * 10^7

y = 2.30 * 10^7kg.

Hence, the biomass weighs 2.30 * 10^7 kg after a year

b.

Here, we're to calculate the time it'll take the biomass to get to 4*10^7 kg

Substitute 4*10^7 for y in (2)

2/7e^0.78t = 4*10^7/(6*10^7 - 4*10^7)

2/7e^0.78t = 4*10^7/2*10^7

2/7e^0.78t = 2

e^0.78t = (2*7)/2

e^0.78t = 2

t = 2 * 1/0.78

t = 2.56 years

Hence, it'll take 2.56 years to get to 4*10^7kg

8 0

3 years ago

URGENT!!

Lapatulllka [165]

Answer:

f[g(4)] = 4

Step-by-step explanation:

Given table:

$\begin{array}{| c | c | c | c | c | c |}\cline{1-6} x & -6 & -4 & 1 & 3 & 4\\\cline{1-6} f(x) & 4 & -1 & -6 & 1 & 3 \\\cline{1-6} g(x) & 1 & 4 & 3 & -4 & -6 \\\cline{1-6}\end{array}$

f[g(4)] is a composite function.

When calculating <u>composite functions</u>, always work from inside the brackets out.

Begin with g(4): g(4) is the value of function g(x) when x = 4.

From inspection of the given table, g(4) = -6

Therefore, f[g(4)] = f(-6)

f(-6) is the value of function f(x) when x = -6.

From inspection of the given table, f(-6) = 4

Therefore, f[g(4)] = 4

3 0

2 years ago

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