What is the domain of f g (x)? f(x)=x+5 g(x)=4x

SOS HURRY 25 POINTS

dezoksy [38]

Answer:

5,000 / 1.35= 3,703.70 is last months profit

Step-by-step explanation:

I hope this helps :)

8 0

3 years ago

A rectangle has side lenghs X +2 and 3X -1 write an expression that represents the perimeter of the rectangle then simplify the

pshichka [43]

Answer: Perimeter = 2(L + W) and

as a simplified expression is, 8x + 2

Step-by-step explanation: The length is represented by L and the width is represented by W in the expression above.

However, since we have been given the sides of the rectangle as x + 2 and 3x - 1, we shall substitute for the values of these in the expression representing the perimeter.

2(L + W) can now be written as

2( {x + 2} + {3x - 1} )

2(x + 2 + 3x - 1)

By collecting like terms, we now have

2(4x + 1)

8x + 2.

The expression can now be simplified as 8x + 2

6 0

3 years ago

How to end subscription here ??

photoshop1234 [79]

Answer: You can’t

Step-by-step explanation:

You are stuck here... FOREVER

8 0

3 years ago

Jessie draws triangle ABC on a coordinate grid. The slope of line segment AB is Jessie then transforms triangle

balu736 [363]

Answer:

1) Supports Jessie's Claim

2) Does Not Support Jessi's Claim

3) Supports Jessie's Claim

4) Does Not Support Jessi's Claim

Step-by-step explanation:

The given transformations are;

1) Rotation of 180° around the origin

For a rotation of 180° around the origin, either clockwise or anti clockwise, for a given coordinate of the preimage (x, y), the coordinate of the image is (-x, -y)

Therefore, whereby the slope of the preimage, given two points (0, 0) and (2, 2), = (2 - 0)/(2 - 0) = 1

For the image with the points (0, 0) and (-2, -2), we have;

(-2 - 0)/(-2 - 0) = 1

Therefore, the slope of the preimage and the image are equal

Therefore, supports Jessie's Claim

2) For a reflection across the line y = 2, we have

We note that the line y = 2 is parallel to the x-axis

For a reflection across the x-axis, for a preimage (x, y), we have the coordinates of the image (x, -y)

However for the reflection across the line y = 2, we have;

For a preimage, (x, y), the coordinate of the image is (x, -y+4)

Given two points, of the preimage (0, 0) and (2, 2), we have the image given as (0, 4) and (2, -2 + 4) = (2, 2);

The slope of the preimage is (2 - 0)/(2 - 0) = 1

The slope of the image is (2 - 4)/(2 - 0) = -1

The slope of the line of the preimage and the image are different

Therefore, does Not Support Jessi's Claim

3) For a translation up 1.25 units, we note that the difference in the y and x values of the coordinates of the preimage and the image will be equal when finding the slope, and therefore, the slope of the figure of the preimage and the slope of the figure of the image will be equal

Therefore, supports Jessie's Claim

4) For a reflection across the x-axis, a point on the preimage, with coordinates (x, y) will form a point on the image with coordinates (x, - y)

For a preimage with points (0, 0) and (2, 2), we have the image as (0, 0) and (2, -2)

The slope of the preimage is (2 - 0)/(2 - 0) = 1

The slope of the image is (-2 - 0)/(2 - 0) = -1

The slope of the line of the preimage and the image are different

Therefore, does Not Support Jessi's Claim

6 0

3 years ago

Find equations for the lines through the point (a,

Free_Kalibri [48]

The line y = mx + c has a slope of m.

Parallel line:
A parallel line will also have a slope of m, and should be of the form
y = mx + k
Because the line passes through the point (a,b), therefore
ma + k = b
k = b - ma
The equation of a parallel line is
y = mx + b - ma
= m(x-a) + b

Perpendicular line:
A perpendicular line will have a slope of -1/m, because the product of slopes should be -1.
The equation for a perpendicular line is of the form
y = -(1/m)x + k
Because the line passes through (a,b), therefore
-(1/m)a + k = b
k = b + a/m
The equation for a perpendicular line is
y = -(x/m) + b + a/m
= -(1/m)(x-a) + b

Answer:
Parallel line: $y=m(x-a)+b$
Perpendicular line: $y=- \frac{1}{m}(x-a)+b$

3 0

3 years ago