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2 years ago

Determine whether (3,2) is a solution of y = 3x +2.

Mathematics

1 answer:

Snowcat [4.5K]2 years ago

6 0

Answer:

This point is not a solution to the equivalence

Step-by-step explanation:

Becouse if we put x= 3 then y= 11

$y = 3 \times 3 + 2 = 11$

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3 years ago

Read 2 more answers

50 POINTS FIRST GOOD ANSWER GETS BRAINLIEST

Inessa [10]

Answer:

$f(x)=3+|2x-5|=\left\{ \begin{array}{ll} 2x-2& \quad x \geq 5/2 \\ -2x+8 & \quad x < 5/2 \end{array} \right.$

Step-by-step explanation:

We are given the function:

$f(x)=3+|2x-5|$

Remember that by the definition of absolute value:

$\displaystyle |x|= \left\{ \begin{array}{ll} x & \quad x \geq 0 \\ - x & \quad x < 0 \end{array} \right.$

Our absolute value is:

$|2x-5|$

First, we will find when it becomes 0. Set the equation equal to 0:

$2x-5=0$

Solve for x:

$x=5/2$

So, we can see that for all values greater than x = 5/2, 2x - 5 is positive.

For all values less than x = 5/2, 2x - 5 is negative.

Therefore (the positive case go above, and the negative case go below):

$|2x-5|= \left\{ \begin{array}{ll} 2x-5 & \quad x \geq 5/2 \\ -(2x-5) & \quad x < 5/2 \end{array} \right.$

Finally, we can add a three:

$f(x)=3+|2x-5|=\left\{ \begin{array}{ll} 3+(2x-5) & \quad x \geq 5/2 \\ 3+(-(2x-5)) & \quad x < 5/2 \end{array} \right.$

Simplify if desired:

$f(x)=3+|2x-5|=\left\{ \begin{array}{ll} 2x-2& \quad x \geq 5/2 \\ -2x+8 & \quad x < 5/2 \end{array} \right.$

5 0

2 years ago

Which statement describes the solution set of function f? f(x)= 3x^2 - 4x - 2

Sergio039 [100]

Answer:

Vertex form

( 2 /3 , − 10 /3 )

x and y intercepts

Y intercept ( 2 + √ 10 /3 , 0 ) , ( 2 − √ 10/ 3 , 0 )

X intercept ( 0 , − 2 )

Step-by-step explanation:

6 0

2 years ago

Determine whether (3,2) is a solution of y = 3x +2.​

Determine whether (3,2) is a solution of y = 3x +2.