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MrMuchimi
2 years ago
15

Pls help me. This is a geo quiz and I don’t have a clue what I am doing.

Mathematics
1 answer:
Sunny_sXe [5.5K]2 years ago
4 0

Answer:

x= 43

measure= 142'

Step-by-step explanation:

We know that a triangle has a sum of 190 degrees we have 17' and 21'

add them together = 38

180-38= 142' (2nd part of answer)

3x + 10 = 142

3x= 132

x= 43 (1st part of answer)

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shtirl [24]

Division yields

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Now for partial fractions: you're looking for constants <em>a</em>, <em>b</em>, and <em>c</em> such that

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which gives <em>a</em> + <em>b</em> = 2, <em>c</em> = 0, and 2<em>a</em> = -7, so that <em>a</em> = -7/2 and <em>b</em> = 11/2. Then

\dfrac{2x^2-7}{x(x^2+2)} = -\dfrac7{2x} + \dfrac{11x}{2(x^2+2)}

Now, in the integral we get

\displaystyle\int\frac{x^4+7}{x^3+2x}\,\mathrm dx = \int\left(x+\frac7{2x} - \frac{11x}{2(x^2+2)}\right)\,\mathrm dx

The first two terms are trivial to integrate. For the third, substitute <em>y</em> = <em>x</em> ² + 2 and d<em>y</em> = 2<em>x</em> d<em>x</em> to get

\displaystyle \int x\,\mathrm dx + \frac72\int\frac{\mathrm dx}x - \frac{11}4 \int\frac{\mathrm dy}y \\\\ =\displaystyle \frac{x^2}2+\frac72\ln|x|-\frac{11}4\ln|y| + C \\\\ =\displaystyle \boxed{\frac{x^2}2 + \frac72\ln|x| - \frac{11}4 \ln(x^2+2) + C}

7 0
2 years ago
Please help I will give 10 points answer both questions
seropon [69]
Question 4:
18(A)+7(S)+10(G)=35 lollipops
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I hope that helps in some way. <span />
5 0
3 years ago
Solve the equation: -6p + 14 and 3p - 2
sleet_krkn [62]

Answer:

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Step-by-step explanation:

-6p+14=3p-2\qquad\text{subtract 14 from both sides}\\\\-6p=3p-16\qquad\text{subtract 3p from both sides}\\\\-9p=-16\qquad\text{divide both sides by (-9)}\\\\\boxed{p=\dfrac{16}{9}\to p=1\dfrac{7}{9}}

5 0
2 years ago
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3 years ago
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8 0
2 years ago
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