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Mariulka [41]
3 years ago
11

I don’t know... please help

Mathematics
2 answers:
Lilit [14]3 years ago
7 0

Answer:

Answer D.

Step-by-step explanation:

Glad to help:)

Explanation: The first line is solid and the 2nd is dashed.

Lera25 [3.4K]3 years ago
6 0

Answer:

Add me the page and Ill hook you up

Step-by-step explanation:

 

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Pls help me with this question my teacher gave me
densk [106]

Answer:

none

Step-by-step explanation:

becàuse it has thesame masses

7 0
3 years ago
: John wants to move from point A to point B. To avoid the pond, he must walk 36 m south and 49 m east. However, he wants to go
just olya [345]

Answer:

60.80

Step-by-step explanation:

6 0
3 years ago
Would you be more or less likely to take a job in which the type of work is enjoyable to you? Why?
OverLord2011 [107]
More likely because you are doing a job that you enjoy doing.
3 0
3 years ago
An=an-1+6an-2 <br> n&gt;2 a0=3 a1=6
Svetach [21]
\begin{cases}a_0=3\\a_1=6\\a_n=a_{n-1}+6a_{n-2}&\text{for }n>2\end{cases}

Let the generating function for a_n be

A(x)=\displaystyle\sum_{n\ge0}a_nx^n

Multiplying both sides by x^{n-2}

a_nx^{n-2}=a_{n-1}x^{n-2}+6a_{n-2}x^{n-2}

Summing both sides over the non-negative integers greater than or equal to 2 gives

\displaystyle\sum_{n\ge2}a_nx^{n-2}=\sum_{n\ge2}a_{n-1}x^{n-2}+6\sum_{n\ge2}a_{n-2}x^{n-2}
\displaystyle\frac1{x^2}\sum_{n\ge2}a_nx^n=\frac1x\sum_{n\ge1}a_nx^n+6\sum_{n\ge0}a_nx^n
\displaystyle\frac1{x^2}\left(\sum_{n\ge0}a_nx^n-a_0-a_1x\right)=\frac1x\left(\sum_{n\ge0}a_nx^n-a_0\right)+6\sum_{n\ge0}a_nx^n
\displaystyle\frac1{x^2}\left(A(x)-3-6x\right)=\frac1x\left(A(x)-3\right)+6A(x)
A(x)=\dfrac{3x+3}{1-x-6x^2}
A(x)=\dfrac3{5(1+2x)}+\dfrac{12}{5(1-3x)}

For |x|, the two series converge to

\displaystyle A(x)=\frac35\sum_{n\ge0}(-2x)^n+\frac{12}5\sum_{n\ge0}(3x)^n
\implies A(x)=\displaystyle\sum_{n\ge0}\dfrac{3(-2)^n+12(3)^n}5x^n
a_n=\dfrac{3(-2)^n+12(3)^n}5=\dfrac{3(-2)^n+4(3)^{n+1}}5
5 0
3 years ago
..........................................
EleoNora [17]

Answer:

a. 6

b. 2

c. 1

Step-by-step explanation:

You can tell by looking at the Venn Diagram

Good luck!

7 0
3 years ago
Read 2 more answers
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