What happens to light when it strikes a smooth shiny surface?

Mathematics

2 answers:

user100 [1]3 years ago

8 0

Answer:

When light strikes an object, its rays can be either absorbed or reflected. A solid black object absorbs almost all light, while a shiny smooth surface, such as a mirror, reflects almost all light back. When reflected off a flat mirror, light bounces off at an angle equal to the angle it struck the object.

Step-by-step explanation:

ELEN [110]3 years ago

6 0

Step-by-step explanation:

Light reflects from a smooth surface at the same angle as it hits the surface. For a smooth surface, reflected light rays travel in the same direction. This is called specular reflection. For a rough surface, reflected light rays scatter in all directions.

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<h3>Answers:</h3>

$W(-2,-1) \to \\W \ ' \ (-4,4)\\\\X(0,2) \to \\X \ ' \ (0,4)\\\\Y(3,-1) \to \\Y \ ' \ (6,-2)\\\\V(-2,-1) \to \\V \ ' \ (-4,-2)\\\\$

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Explanation:

The scale factor is 2, which means we double each coordinate of each point. The general rule is $(x,y) \to (kx,ky)$ with k = 2. So we can say the more specific dilation rule is $(x,y) \to (2x,2y)$

Something like W(-2,2) moves to W ' (-4, 4) after multiplying each coordinate by 2. Do the same for the other points as well.

The given preimage points

V = (-2, -1)
W = (-2, 2)
X = (0, 2)
Y = (3, -1)

will dilate to the corresponding image points

V ' = (-4, -2)
W ' = (-4, 4)
X ' = (0, 4)
Y ' = (6, -2)

as shown below. This causes the image to be larger compared to the preimage (since the scale factor is larger than 1). Any given point is twice as far from the origin as compared to before, which in turn means the distance between any two points is twice as much.