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miss Akunina [59]
2 years ago
14

Two electricians are assigned to work on a remote control wiring job. One electrician works 8 1/2 hours each day, and the other

electrician works 2 1/2 hours each day. If both work for 5 days, how many hours longer does
the first electrician work than the second electrician?
Mathematics
1 answer:
klasskru [66]2 years ago
6 0
8.5 • 5 = 42.5
2.5 • 5 = 12.5
42.5 - 12.5 = 30
The first electrician worked 30 hours longer than the second electrician.
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Subtract 2 from the term number

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Charlotte’s weekly paycheck is based on the number of hours worked during the week and on the weekend. If she works 13 hours dur
Schach [20]
X: earn per  hour during the week
y: earn per hour during the weekend

13x + 14y = 250.90
15x + 8y = 204.70

Multiply the first equation by 4 and the second equation by 7

52x + 56y = 1003.6
105x + 56y = 1432.90

Subtract the first equation from the second:

 53x = 429.30

x = 429.30/ 53
x = 8.10

Solve any of the equation for y:

15x + 8y = 204.70

y = [204.70 - 15(8.10)]/8 = 10.40

y - x = 10.40 -8.10 = 2.30

Answer: she earns $2.30 per hour more during the weekend than during the week.


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3 years ago
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Q2) The following travel times were measured for vehicles traversing a 2,000 ft. segment of an arterial: Vehicle Travel Time (s)
adelina 88 [10]

Answer:

TMS = 45.78 m/s

SMS = 45.66 m/s

Step-by-step explanation:

Vehicle Travel Time (s)

1 40.5

2 44.2

3 41.7

4 47.3

5 46.5

6 41.9

7 43.0

8 47.0

9 42.6

10 43.3

Time mean speed and space mean speed are parameters used to express the speed of a group of vehicles in traffic flow.

Time mean speed is given as the average speed of all the cars

The speed for each vehicle is calculated by dividing the (2000 ft) distance by the time taken by each vehicle to complete that segment of the journey.

Let vehicle = V

Travel time = time

Speed = s

V | Time | speed (ft/s)

1 | 40.5 | 49.383

2 | 44.2 | 45.249

3 | 41.7 | 47.962

4 | 47.3 | 42.283

5 | 46.5 | 43.011

6 | 41.9 | 47.733

7 | 43.0 | 46.512

8 | 47.0 | 42.553

9 | 42.6 | 46.948

10| 43.3 | 46.189

TMS = (Σsᵢ)/N

Σsᵢ = (49.383+45.249+47.962+42.283+43.011+47.733+46.512+42.553+46.948+46.189)

Σsᵢ = 457.823

N = number of vehicles = 10

TMS = 457.823 ÷ 10 = 45.7823 = 45.782 m/s

b) Space mean speed is given as

SMS = N ÷ [Σ (1/sᵢ)]

V | Time | speed | (1/sᵢ)

1 | 40.5 | 49.383 | 0.02025

2 | 44.2 | 45.249 | 0.02210

3 | 41.7 | 47.962 | 0.02085

4 | 47.3 | 42.283 | 0.02365

5 | 46.5 | 43.011 | 0.02325

6 | 41.9 | 47.733 | 0.02095

7 | 43.0 | 46.512 | 0.02150

8 | 47.0 | 42.553 | 0.02350

9 | 42.6 | 46.948 | 0.02130

10| 43.3 | 46.189 | 0.02165

Σ (1/sᵢ) = (0.02025+0.02210+0.02085+0.02365+0.02325+0.02095+0.02150+0.02350+0.02130+0.02165)

Σ (1/sᵢ) = 0.219

SMS = 10 ÷ [Σ (1/sᵢ)] = 10 ÷ 0.219

SMS = 45.662 m/s

Hope this Helps!!!

4 0
3 years ago
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