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Citrus2011 [14]
3 years ago
13

The diagram shows a sector OAPB of a circle, centre O.

Mathematics
1 answer:
Iteru [2.4K]3 years ago
5 0

Answer:

4.44 cm²

Step-by-step explanation:

If the diagram attached below is required to complete the question,

Applying,

Area of the shaded segment(A) = Area of the sector- area of the triangle

A = (πr²∅/360)-(r²sin∅/)2................ Equation 1

Where r = radius of the circle, ∅ = angle at the center of the circle,π = pie

From the question,

Given: r = 5.4 cm, ∅ = 72°

Constant: π = 3.14

Substitute these values into equation 1

A = (3.14×5.4²×72/360)-(5.4²/2×sin72)

A = 18.31-13.87

A = 4.44 cm²

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Answer:

1.4x10^-7

Step-by-step explanation:

For Problem 6

First we would divide the first numbers together so 7.84 / 5.6 = 1.4

We then would add the exponenites together so -3+-4=-7

Leading our awnser to be 1.4x10^-7

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3 years ago
If the revenue for the week is $2000, and labor cost consists of two workers earning $8 per hour who work 40hours each, what is
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The percentage of the revenue is 32% hope this helps!
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Transversal t cuts parallel lines a and bas shown in the diagram. Which equation is necessarily true?
irina1246 [14]

Answer:

Option D is correct

Step-by-step explanation:

Using the given diagram, we want to know the equation that is true

Option A is wrong as both are on a straight line and in fact should add up to equal 180 and not be equal to each other

Option B is not correct as both are supplementary and does not equal each other

Option C is not correct, both are corresponding to each other and should not add up to 90

Option D is correct

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4 0
2 years ago
6th grade math help me pleaseeee
Gnoma [55]

Answer:

1.4

Step-by-step explanation:

9.5+0.9t

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3 0
2 years ago
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Use trigonometric identities to solve each equation within the given domain.
katrin [286]

Recall that the tangent function is defined by

tan(<em>x</em>) = sin(<em>x</em>)/cos(<em>x</em>)

Also recall the double angle identity for sine,

sin(2<em>x</em>) = 2 sin(<em>x</em>) cos(<em>x</em>)

Then the equation is the same as

3 sin(<em>x</em>)/cos(<em>x</em>) = 4 sin(<em>x</em>) cos(<em>x</em>)

Move everything to one side to prepare to factorize:

3 sin(<em>x</em>)/cos(<em>x</em>) - 4 sin(<em>x</em>) cos(<em>x</em>) = 0

sin(<em>x</em>)/cos(<em>x</em>) (3 - 4 cos²(<em>x</em>)) = 0

As long as cos(<em>x</em>) ≠ 0, we can omit the term in the denominator, so we're left with

sin(<em>x</em>) (3 - 4 cos²(<em>x</em>)) = 0

and so

sin(<em>x</em>) = 0   <u>or</u>   3 - 4 cos²(<em>x</em>) = 0

sin(<em>x</em>) = 0   <u>or</u>   cos²(<em>x</em>) = 3/4

sin(<em>x</em>) = 0   <u>or</u>   cos(<em>x</em>) = ±√3/2

On the interval [0, 2<em>π</em>),

• sin(<em>x</em>) = 0 for <em>x</em> = 0 and <em>x</em> = <em>π</em>

• cos(<em>x</em>) = √3/2 for <em>x</em> = <em>π</em>/6 and <em>x</em> = 11<em>π</em>/6

• cos(<em>x</em>) = -√3/2 for <em>x</em> = 5<em>π</em>/6 and <em>x</em> = 7<em>π</em>/6

(None of these <em>x</em> make cos(<em>x</em>) = 0, so we don't have to omit any extraneous solutions.)

6 0
3 years ago
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