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3 years ago

10

Determine a solution for the linear inequality graphed here.

1 answer:

dangina [55]3 years ago

5 0

Answer:

C

Step-by-step explanation:

Test all of the coordinates given to you.

Starting with the X's. (because they are all positive, move to the right.)

Go right in the direction based on the number given

then go up or down for the Y's depending on the number given.

By following this, you will find that 3 of the solutions do not end up in the shaded area but one. 0,0 is the only solution that ends up in the orange area.

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Evaluate the expression 2b^3+5 (BTW I did the first part it's 3 but I need the second part)

andrey2020 [161]

To find the exact answer based on the last step, " $2(3)^3+5$ ", you must use PEMDAS (attached image below)

$2(3)^3+5=2*27+5=54+5=59$

Thus the answer is <u>59</u>.

Hope that helps!

4 0

3 years ago

The mean blood pressure of the 10 adults in exercise 6 is ?

Zigmanuir [339]

Snsjwjjwjsjajajjsjdbus

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3 years ago

Look at pic and answer pls

PtichkaEL [24]

(a) $x^{-5}$

(b) $3x^{-7}$

(c) $$\frac{4}{3}x^4$

Solution:

To write each of the given expression in the form $ax^n$ :

(a) $\frac{x^3}{x^8}$

Using exponential rule: $\frac{a^x}{a^y}=a^{x-y}$

$$\frac{x^3}{x^8}=x^{3-8}$

$$\frac{x^3}{x^8}=x^{-5}$

(b) $\frac{6x}{2x^8}$

Divide numerator and denominator by the common factor 2, we get

$$\frac{6x}{2x^8}=\frac{3x}{x^8}$

Using exponential rule: $\frac{a^x}{a^y}=a^{x-y}$

$$=3x^{1-8}$

$$\frac{6x}{2x^8} =3x^{-7}$

(c) $\frac{28x^6}{21x^2}$

Divide numerator and denominator by the common factor 7, we get

$$\frac{28x^6}{21x^2}=\frac{4x^6}{3x^2}$

Using exponential rule: $\frac{a^x}{a^y}=a^{x-y}$

$$=\frac{4}{3}x^{6-2}$

$$\frac{28x^6}{21x^2}=\frac{4}{3}x^4$

8 0

3 years ago

What is 22 to the seventh power

Nimfa-mama [501]

Answer:

2494357888

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Write the equation of the parabola that has its x-intercepts at (1+<img src="https://tex.z-dn.net/?f=%5Csqrt%7B5%7D" id="TexForm

VladimirAG [237]

Answer:

$y=2x^2-4x-8$

Step-by-step explanation:

<u>Factored form of a parabola</u>

$y=a(x-p)(x-q)$

where:

p and q are the x-intercepts.
a is some constant.

Given x-intercepts:

(1+√5, 0)
(1-√5, 0)

Therefore:

$\implies y=a(x-(1+\sqrt{5}))(x-(1-\sqrt{5}))$

$\implies y=a(x-1-\sqrt{5})(x-1+\sqrt{5})$

To find a, substitute the given point (4, 8) into the equation and solve for a:

$\implies a(4-1-\sqrt{5})(4-1+\sqrt{5})=8$

$\implies a(3-\sqrt{5})(3+\sqrt{5})=8$

$\implies4a=8$

$\implies a=2$

Therefore, the equation of the parabola in factored form is:

$\implies y=2(x-1-\sqrt{5})(x-1+\sqrt{5})$

Expand so that the equation is in standard form:

$\implies y=2(x^2-x+\sqrt{5}x-x+1-\sqrt{5}-\sqrt{5}x+\sqrt{5}-5)$

$\implies y=2(x^2-x-x+\sqrt{5}x-\sqrt{5}x+\sqrt{5}-\sqrt{5}+1-5)$

$\implies y=2(x^2-2x-4)$

$\implies y=2x^2-4x-8$

6 0

2 years ago