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PilotLPTM [1.2K]
3 years ago
15

To see how costly it would be for other people to compete a similar cycling tour, you decide to work out two averages and compar

e. The average amount spent by members of cycle group A was?
Person 1 £500
Person 2 £600
Person 3 £900
Person 4 £450

Group B
Person 1 £700
Person 2 £500
Person 3 £680
Person 4 £500
The average amount spent by members of group B was?

Which group had the lower average spend?
Mathematics
1 answer:
Damm [24]3 years ago
4 0

Group A

Money spent by Person 1 = £500

Money spent by Person 2 = £600

Money spent by Person 3 = £900

Money spent by Person 4 = £450

Sum of money spent by group A = £2,450

Average money spent by group A = \frac{2,450}{4}

⇒ Average money spent by group A = £612.5

Group B

Money spent by Person 1 = £700

Money spent by Person 2 = £500

Money spent by Person 3 = £680

Money spent by Person 4 = £500

Sum of money spent by group B = £2,380

Average money spent by group B = \frac{2,380}{4}

⇒ Average money spent by group B = £595

Hence, Group B had lower average spend.

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Una persona que está situada entre dos montañas emite un sonido, si percibe el primer eco a los 2 seg, y el siguiente a los 3 se
Goryan [66]

Answer:

1715 metros

Step-by-step explanation:

Lo que debemos hacer es calcular la distancia del primer y del segundo eco.

Debemos conocer la velocidad del sonido que en términos generales es 343 m/s, por lo tanto, la distancia sería igual a:

v = d/t => d = v*t

d1 = 343*2 = 686 metros

d2 = 343*3 = 1029 metros

La separación sería la suma de ambas distancias así:

686 + 1029 = 1715

1715 metros sería la distancia de separación entre ambas montañas.

3 0
3 years ago
1 and 2 are supplementary.If m1 = (3x-17) and m2= (5x+21) find the value of x
torisob [31]

Answer:

22

Step-by-step explanation:

m1 + m2 = 180

3x - 17 + 5x + 21 = 180

3x + 5x + 21 - 17 = 180

8x + 4 = 180

8x = 180 - 4

8x = 176

x = 176 / 8

x = 22

7 0
3 years ago
Find the sum of 3+9+27...+6561
Nikolay [14]
The sum of the first n terms of a geometric series with first term a₁ and common ratio r is given by the formula
S_{n}=a_{1}\cdot\dfrac{r^{n}-1}{r-1}

Then your sum is
\sum\limits_{n=1}^{8}3^{n}=3\cdot\dfrac{3^{8}-1}{3-1}=9840

The sum of this geometric series with first term 3 and common ratio 3 is ...
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7 0
4 years ago
How many thousands equals 90 hundreds
sp2606 [1]
Hello!

90 hundreds = 9,000. 9 x 1,000 = 9,000. There are 9 thousands in 90 hundreds.

Hope l heIped!
8 0
4 years ago
I need help with #4. Please help. I have to show all work so please explain
cupoosta [38]

9514 1404 393

Answer:

  5

Step-by-step explanation:

Use the distance formula.

  d = √((x2 -x1)² +(y2 -y1)²)

  d = √((4 -0)²+(3 -0)²) = √(4² +3²) = √(16 +9) = √25

  d = 5

The distance between the two points is 5 units.

_____

<em>Additional comment</em>

The most commonly seen Pythagorean triples are (3, 4, 5), (5, 12, 13), (7, 24, 25), (8, 15, 17) and their multiples.

In problem 4, once you see that the differences of the coordinates are 3 and 4, you can consult your memory of the (3, 4, 5) Pythagorean triple to recognize the hypotenuse length of a triangle with sides 3 and 4 is 5.

Similarly, in problem 5, you recognize the coordinate differences as 5 and 12, so you know from the (5, 12, 13) Pythagorean triple that the distance will be 13.

8 0
3 years ago
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