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PilotLPTM [1.2K]
3 years ago
15

To see how costly it would be for other people to compete a similar cycling tour, you decide to work out two averages and compar

e. The average amount spent by members of cycle group A was?
Person 1 £500
Person 2 £600
Person 3 £900
Person 4 £450

Group B
Person 1 £700
Person 2 £500
Person 3 £680
Person 4 £500
The average amount spent by members of group B was?

Which group had the lower average spend?
Mathematics
1 answer:
Damm [24]3 years ago
4 0

Group A

Money spent by Person 1 = £500

Money spent by Person 2 = £600

Money spent by Person 3 = £900

Money spent by Person 4 = £450

Sum of money spent by group A = £2,450

Average money spent by group A = \frac{2,450}{4}

⇒ Average money spent by group A = £612.5

Group B

Money spent by Person 1 = £700

Money spent by Person 2 = £500

Money spent by Person 3 = £680

Money spent by Person 4 = £500

Sum of money spent by group B = £2,380

Average money spent by group B = \frac{2,380}{4}

⇒ Average money spent by group B = £595

Hence, Group B had lower average spend.

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Please help, me find the area of Letter E.​
Radda [10]

Answer:

7.005 m^2.

Step-by-step explanation:

We can split this into one vertical rectangle   3.45 * 0.9 m^2

2 rectangles 2 * 0.75  = 1.5 m^2

1 rectangle 1.2 * 0.75 m^2

=  3.105 + 2 * 1.5 + 0.9

= 7.005 m^2.

7 0
3 years ago
By first calculating the size of angle LMN,
Naily [24]

Step-by-step explanation:

Hope it helps.... that is how I did it

4 0
3 years ago
Several different bus routes stop at the corner of Second St. and Lincoln Ave. A Wilkenson bus arrives every 21 minutes and a Ha
Olin [163]

Answer:

Both buses will arrive at the stop at 6:52 AM

Step-by-step explanation:

Wilkenson Bus = Arrives every 21 minutes

Harris Road Bus = Arrives every 15 minutes

Let's find the Least Common Multiple (LCM) of 21 and 15. LCM is found, listing the prime factors of each numbers and then multiplying each factor the greatest number of times it occurs in either numbers:

LCM 21 = 3 × 7

LCM 15 = 3 × 5

LCM (21 , 15) = 3 × 7 × 5  = 105

In 105 minutes both buses will arrive at the same time again

105 minutes = 1 h 45 min

5:07 AM + 1h 45 min = 6:52 AM

3 0
3 years ago
explain why a student who runs 3/4 mile in 6 minutes is faster than a student who runs 1/2 mile in 5 minutes.​
luda_lava [24]

Answer:

A student who runs 3/4 mile in 6 minutes is faster than a student who runs 1/2 mile in 5 minutes because when you simplify both fractions to per minute, the student who ran 3/4 mile in 6 minutes (1/8 mile per min) ran faster than the student who ran 1/2 mile in 5 minutes (1/10mile in 1 min).

Step-by-step explanation:

\frac{3/4mile}{6min} divided by 6 to get per min =

1/8 mile per min

6 0
3 years ago
Which of the following expressions is equivalent to 6m - 10?
anastassius [24]
<span>6m - 10

Test each answer to find out which one's correct.
</span><span>2(3m + 5)
6m + 10

</span><span>-2(5 - 3m)
-10 + 6m
6m - 10

</span><span>2(3m - 10)
</span>6m - 20

The correct answer is <span>-2(5 - 3m).
</span>
3 0
3 years ago
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