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musickatia [10]
2 years ago
6

Did I get this right? Please help me

Mathematics
2 answers:
Mrac [35]2 years ago
6 0

Answer:

yes it's but I am not good at it but also

according to me that correct

Irina-Kira [14]2 years ago
4 0

Answer:

yeah ur right lol

Step-by-step explanation:

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(-102.75) ÷(-3) round to the nearest hundredth
astra-53 [7]

Answer:34.17

Step-by-step explanation:

(-102.5) ➗ (-3)=34.17

6 0
3 years ago
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What is the Difference between elimination method and indirect method​
soldier1979 [14.2K]

Answer:

Indirect method actually follows the same set of procedure as the direct method except that it begins with net income unlike the elimination method reduced a given system that indicates a system has no unique solution.

6 0
2 years ago
7.6x = 64 is approximately 3.05.<br> is this the solution?
lisov135 [29]
7.6x = 64
x = 64/7.6
x = <span> <span> <span> 8.4210526316 </span> </span> </span>
So, 3.05 is NOT the solution

3 0
3 years ago
Please help ASAP URGENT Will mark Brianlest
PIT_PIT [208]

Answer:

A

Step-by-step explanation:

i used the process of elimination and got rid of answers that didnt make sense but based on the info given i could tell that x was 5 months because of where the point of 5 is on the graph

8 0
3 years ago
Read 2 more answers
Find an equation of the line passing through the pair of points. Write the equation in the form Ax +By = C.
Alexxandr [17]

9514 1404 393

Answer:

  5x -y = -37

Step-by-step explanation:

One way to find the coefficients A and B is to use the differences of the x- and y-coordinates:

  A = Δy = y2 -y1 = 2 -(-3) = 5

  B = -Δx = -(x2 -x1) = -(-7 -(-8)) = -1

Then the constant C can be found using either point.

  5x -y = 5(-7) -2 = -37

The equation of the line is ...

  5x -y = -37

_____

<em>Additional comment</em>

This approach comes from the fact that the slope of a line is the same everywhere.

  \dfrac{y-y_1}{x-x_1}=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{\Delta y}{\Delta x}\\\\\Delta x(y-y_1)=\Delta y(x-x_1)\qquad\text{cross multiply}\\\\\Delta y(x-x_1)-\Delta x(y-y_1)=0\qquad\text{subtract y term}\\\\\Delta y(x) -\Delta x(y) = \Delta y(x_1)-\Delta x(y_1)\qquad\text{Ax+By=C form}

The "standard form" requires that A be positive, so we chose point 1 and point 2 to make sure that was the case.

5 0
2 years ago
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