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Vinil7 [7]
2 years ago
10

Figure ABCD is transformed to figure A prime B prime C prime D prime, as shown: A coordinate grid is shown from negative 5 to 0

to 5 on both x -and y-axes. A polygon ABCD has A at ordered pair 1, 3, B at ordered pair 3, 4, C at ordered pair 2, 1, D at ordered pair 1, 1. A polygon A prime B prime C prime D prime has A prime at ordered pair negative 3, 3, B prime at ordered pair negative 5, 4, C prime at ordered pair negative 4, 1, D prime at ordered pair negative 3, 1. Which of the following sequences of transformations is used to obtain figure A prime B prime C prime D prime from figure ABCD?
Mathematics
1 answer:
Darya [45]2 years ago
8 0

Figure ABCD was translated 2 units to the right so as to obtain figure A'B'C'D'

<h3>What is transformation?</h3>

Transformation is the movement of a point from its initial location to a new location. Types of transformation are t<em>ranslation, reflection, rotation and dilation.</em>

Figure ABCD was translated 2 units to the right so as to obtain figure A'B'C'D'

Find out more on transformation at: brainly.com/question/4289712

#SPJ1

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Corey walked three blocks east and then six blocks north. All the blocks were the same length. What is the value of the slope of
serg [7]
You can set up an equation of a line where it has a slope-intercept form written as y=mx + b where m is the slope and b is the y-intercept. The slope is calculated by the change in y over  the change in x. Hope this answers the question. Have a nice day
8 0
3 years ago
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Any proof professionals please help!!!!!!!! We don't drag or drop answers in we have to write them out ourselves!!!! It's worth
ss7ja [257]

Answer:

See below.

Step-by-step explanation:

1. Given.

2. Given

3. Definition of  angle bisector.

4. BD ⊥ AC

5. They are both right angles.

6. This is common on to both triangle  ABD and CBD.

7. Congruent by 2 angles and the corresponding side ( ASA?)

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7 0
3 years ago
Explain your answer !! <br> Have a nice day
Vilka [71]

Answer:

what grade is this? I'm in 6th grade

5 0
3 years ago
Henry correctly subtracted 3p+5/3p from 4p+3/p-2 and got 12p2+9p-3p2+p10/(p-2)(3p). What is the simplified difference?
boyakko [2]

Answer:

Simplified expression is \frac{9p^{2}+10p+10}{3p(p-2)}

Step-by-step explanation:

In this question the two fractions are \frac{4p+3}{p-2} and \frac{3p+5}{3p}

Now Henry subtracts first fraction from the second.

=\frac{4p+3}{p-2}-\frac{3p+5}{3p}

=\frac{(4p+3)3p-(3p+5)(p-2)}{3p(p-2)}

=\frac{12p^{2}+9p-(3p^{2}+5p-6p-10)}{3p(p-2)}

=\frac{12p^{2}+9p-3p^{2}+p+10}{3p(p-2)}

=\frac{9p^{2}+10p+10}{3p(p-2)}

So the simplified difference is \frac{9p^{2}+10p+10}{3p(p-2)}

5 0
4 years ago
Find cot x if sin x cot x csc x = √2
dsp73

Here you go

Answer:

cot

x

=

√

2

Explanation:

note that the function # cscx = 1/sinx

hence  

sin

x

×

cot

x

×

1

sin

x

=

√

2

cancelling out the  

sin

x

terms

gives  

cot

x

=

√

2

Plz mark me as brainsliest

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3 years ago
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