Answer with Step-by-step explanation:
From the table, we can see that:
f(-3)=1 , f(-2)=2 , f(-1)=3 and f(0)=4
ƒ(x) = 4x
f(0)=4×0
=0 ≠4
Hence, this function does not rule for the table
ƒ(x) = x – 4
f(0)=0-4
= -4 ≠4
Hence, this function does not rule for the table
ƒ(x) = –4 – x
f(0)= -4-0
= -4 ≠4
Hence, this function does not rule for the table
Hence, ƒ(x) = x + 4 is the correct option
