Answer: Yes. (gof)(0) = -5
(gof)(0) means you will find the function of g(f(0)), which means we will find f(0) and plug that value in for x in the function g(x)
We know f(0) is -1, so we can plug -1 into the equation of g(x)
(gof)(0) = (-1) - 4
(gof)(0) = -5
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*If you need me to do #5, DM me!
3. The area of a triangle can be given by (just plug and chug as always):

The area of the triangle is
6ft².
4. I will divide into a triangle and a rectangle (because the actual equation for the area of a pentagon requires it to be a perfect pentagon). Let's do the triangle first (height is 3 because you subtract 12 from 15):


Now we just add them:

So, the area of that pentagon is
108m².
5. You are actually wrong on this one because the area of a triangle is:

So, just halve your answer and it will be correct.
6. We can just split it into 4 triangles of equal area and then multiply the area of 1 triangle by 4 to get the total area. Let's do just that:

Multiply by 4 to get total area:

So, the area of the given rhombus is
25cm².
Remember that both the denominator and the square root function cannot have values less than 0. So to figure what values can go into each we need to do a little math. Set both the denominator and the under the radical equal to 0
x + 2 = 0 x - 3 = 0
x = -2 x = 3
Since they must be those numbers or bigger 3 is the larger of the 2 the final answer is
x >= 3 Type in greater than into the box