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3 years ago

Who can help me with my last question?

Mathematics

2 answers:

Setler79 [48]3 years ago

8 0

Answer:

wait what was the question i might be able to help if i know what it is

Scrat [10]3 years ago

3 0

Where the question cuz i don’t see it

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What is bigger, 3/4 or 2/3

valentina_108 [34]

If you split a circle in to 4, and color in 3 of the 4 pieces you will find that 3/4 are bigger than 2/3

6 0

3 years ago

Read 2 more answers

Write an equation for the function graphed below. k(t)=

zloy xaker [14]

Answer:

I think that the equation would be Y= -2X^2-4X-4 .

Step-by-step explanation:

Hope it wad helpful :)

5 0

2 years ago

Make a table of ordered pairs for the equation.

soldier1979 [14.2K]

X y
-2 -3
-1 -1
0 1
1 3
2 5

i can’t graph it, but i hope this helps

4 0

3 years ago

Which of the following is equivalent to (a + b/2) ^2?

myrzilka [38]

Answer:

a^2 + 4a/b + 4/b^2

Step-by-step explanation:

Which of the following is equivalent to (a + b/2) ^2?

4 0

2 years ago

Find the solution set of this inequality|10x+20| ≤10

Pavlova-9 [17]

Answer:

solution is

[-3,-1]

Step-by-step explanation:

we are given

$|10x+20|\leq 10$

Firstly, we will find critical values

so, let's assume it is equal

$|10x+20|= 10$

now, we can break absolute sign

For $|10x+20|= -(10x+20)$ :

$-(10x+20)= 10$

we can solve for x

$-10x-20= 10$

Add both sides by 20

$-10x-20+20= 10+20$

$-10x= 30$

Divide both sides by -10

and we get

$x=-3$

For $|10x+20|= (10x+20)$ :

$(10x+20)= 10$

we can solve for x

$10x+20= 10$

Subtract both sides by 20

$10x+20-20= 10-20$

$10x= -10$

Divide both sides by 10

and we get

$x=-1$

so, critical values are

$x=-3$

$x=-1$

now, we can draw a number line and locate these values

and then we can check inequality on each intervals

For $(-\infty,-3)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-5

$|10\times -5+20|\leq 10$

$|-50+20|\leq 10$

$30\leq 10$

so, this is FALSE

For $[-3,-1]$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-2

$|10\times -2+20|\leq 10$

$|-20+20|\leq 10$

$0\leq 10$

so, this is TRUE

For $(-1,\infty)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=0

$|10\times 0+20|\leq 10$

$|0+20|\leq 10$

$20\leq 10$

so, this is FALSE

so, solution is

[-3,-1]

7 0

3 years ago

Who can help me with my last question?​

Who can help me with my last question?