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3 years ago

Who can help me with my last question?

Mathematics

2 answers:

Setler79 [48]3 years ago

8 0

Answer:

wait what was the question i might be able to help if i know what it is

Scrat [10]3 years ago

3 0

Where the question cuz i don’t see it

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Solve using law of sines or law of cosines!

malfutka [58]

Answer:

Part 5) The length of the ski lift is $1.15\ miles$

Part 6) The height of the tree is 18.12 m

Step-by-step explanation:

Part 5)

Let

A -----> Beginning of the ski lift

B -----> Top of the mountain

C -----> Base of mountain

we have

$b=0.75\ miles$

$A=20\°$

$C=180\°-50\°=130\°$ ----> by supplementary angles

Find the measure of angle B

Remember that the sum of the interior angles must be equal to 180 degrees

$B=180\°-A-C$

substitute

$B=180\°-20\°-130\°=30\°$

Applying the law of sines

$\frac{b}{sin(B)}=\frac{c}{sin(C)}$

substitute

$\frac{0.75}{sin(30\°)}=\frac{c}{sin(130\°)}$

$c=\frac{0.75}{sin(30\°)}(sin(130\°))$

$c=1.15\ miles$

Par 6)

see the attached figure with letters to better understand the problem

Applying the law of sines in the right triangle BDC

In the right triangle BDC 20 degrees is the complement of 70 degrees

$\frac{BC}{sin(70\°)}=\frac{x}{sin(20\°)}$

$BC=(sin(70\°))\frac{x}{sin(20\°)}$ -----> equation A

Applying the law of sines in the right triangle ABC

In the right triangle ABC 50 degrees is the complement of 40 degrees

$\frac{BC}{sin(40\°)}=\frac{x+15}{sin(50\°)}$

$BC=(sin(40\°))\frac{x+15}{sin(50\°)}$ -----> equation B

Equate equation A and equation B and solve for x

$(sin(70\°))\frac{x}{sin(20\°)}=(sin(40\°))\frac{x+15}{sin(50\°)}\\\\2.7475x=0.8391(x+15)\\\\2.7475x=0.8391x+12.5865\\\\2.7475x-0.8391x=12.5865\\\\x=6.60\ m$

Find the value of BC

$BC=(sin(70\°))\frac{6.6}{sin(20\°)}$

$BC=18.12\ m$

therefore

The height of the tree is 18.12 m

5 0

4 years ago

A Samsung Galaxy tablet sells for $299, which is marked up 40% of the selling price. What's the cost of the tablet?

Serjik [45]

The cost will be 119.6.

8 0

3 years ago

Read 2 more answers

Two triangles are similar, solve for x if AU = 20x + 108, UB = 273, BC = 703, UV = 44at the4, AV = 372 and AC = 589.

nikklg [1K]

The right information from the figure is:

AU = 20x + 108,
UB = 273,
BC = 703,
UV = 444,
AV = 372 and
AC = 589

The similarity of the two triangles leads to:

[AB] / [AC] = [AU] / [AV]

[AB] = [AU] + [UB] = 20x + 108 + 273 = 20x + 381

=> (20x + 381) / (589) = (20x + 108) / 372

Now you can solve for x.

(372)(20x + 381) = (20x + 108)(589)

=> 7440x + 141732 = 11780x + 63612

=> 11780x - 7440x = 141732 - 63612

=> 4340x = 78120

=> x = 18

Answer: x = 18

3 0

4 years ago

Which operation gives a result of 1.39? sum of 2.39 and -130 sum of 0.63 and 1.25 sum of -2.96 and 4.35 sum of -5.66 and 1.25

wariber [46]

2.39 - 1.30 = 1.09 (no)
0.63 + 1.25 = 1.88 (no)
-2.96 + 4.35 = 1.39 (yes)
-5.66 + 1.25 = 4.41 (no)

4 0

3 years ago

Read 2 more answers

In a company 60% of the workers are women if 1920 people work for the company who aren’t women, how many workers are there in al

Ray Of Light [21]

Answer:

Step-by-step explanation:

if 60% of the workers are women, and we have 1920 total of people

1920x 60/100=1152 women

768 are men

7 0

3 years ago

Who can help me with my last question?​

Who can help me with my last question?