Given: x - 8 > -3. Choose the solution set.

1 answer:

5 0

If you would like to solve the inequality x - 8 > -3, you can do this using the following steps:

<span>x - 8 > -3
</span>x > -3 + 8
x > 5

The correct result would be x > 5.

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Which equation is true about the measure of the angles of the triangle?the measure of angle prq is equal to 100 degreesthe measu

harkovskaia [24]

I believe this question is missing an image. However, I will just tell how how to solve such question and you can apply this solution to the triangle you have.

In any given triangle, the sum of the measure of the three angles must be equal to 180 degrees.
Therefore, for a triangle pqr:
measure angle pqr + measure angle prq + measure angle rqp = 180 degrees

If you have one angle given, then the sum of the other two angles will be equal to 180 - measure of the given angle.

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I GIVE BRAINLIEST PLS HELP

ioda

The answer is 8
Here's why:
${ ( \frac{( {6}^{7}) \times ( {3}^{3}) }{( {6}^{6}) \times ( {3}^{4} ) } )}^{3} = \\ ( \frac{6}{3} ) ^{3} = \\ \frac{216}{27} = 8$
The exponents are subtracted one from another when divided.
$\frac{ a ^{b} }{ {a}^{c} } = {a}^{b - c}$
We can look at the problem this way:
$( \frac{6^{7} }{6 ^{6} } \times \frac{3^{3} }{ {3}^{4} } ) = (6^{7 - 6} \times {3}^{3 - 4} ) = \\ ({6}^{1} \times {3}^{ - 1} )$
Since we have the power of -1 on the 3, we apply this rule:
${a}^{ - b} = \frac{1}{ {a}^{b} }$
Also this rule because we have the power of 1 on the 6:
${a}^{1} = a$
Then we get this:
$(6 \times \frac{1}{3} )^{3} = ( \frac{6}{3} )^{3}$
We apply the rule:
$( \frac{a}{b}) ^{c} = \frac{ {a}^{c} }{ {b}^{c} }$
We get this:
$\frac{{6}^{3} }{ {3}^{3} } = \frac{216}{27} = 8$

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Find the mean of 7, 1, 1, 4, 1, 4 graphically. What is the sum of the number???

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Answer:

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