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Brilliant_brown [7]
3 years ago
12

H(2) = Someone pls help

Mathematics
1 answer:
Anna71 [15]3 years ago
6 0

Replace n with 2 in the bottom equation.

h(2) = h(2 - 1) + 2

h(2) = h(1) + 2

We are given that h(1) is -2. See it?

So, h(2) = -2 + 2, which is 0.

Answer: h(2) = 0.

Got it?

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This soda can is going to be made from aluminum. How many square centimeters of aluminum are needed if the radius r = 3.5 cm and
kari74 [83]

208.81 square centimeters of aluminium are needed

<em><u>Solution:</u></em>

Given that,

Radius = 3.5 cm

Height = 6 cm

We have to find the square centimeters of aluminum needed

So we have to find the surface area of cylinder

<em><u>The surface area of cylinder is given by formula:</u></em>

A = 2 \pi r(h+r)

Where "r" is the radius and "h" is the height of cylinder

<em><u>Substituting the values we get,</u></em>

A  = 2 \times 3.14 \times 3.5 \times (6+3.5)\\\\A = 21.98 \times 9.5\\\\A = 208.81

Thus 208.81 square centimeters of aluminium are needed

8 0
3 years ago
How do you solve this
mars1129 [50]

Answer:

The inquality is always false i think..

Step-by-step explanation:

8 0
4 years ago
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How do I do this -9 - 16m = 7? What are the steps?
nordsb [41]

m = -1

Step-by-step explanation:

-16m = 7 + 9

-16m = 16

m = 16 ÷ -16

m = -1

4 0
3 years ago
HELP ASAP PLZ :)
Natalija [7]

for the triangle...

b=2h

a=(1\2).bh=648

(1/2).2h.h=648

h2=648

h-18|2 in

h=36|2 in

for the rectangle...

L=3+w

a=l+w=648

{3+w}w=648

w2+3w-648=0

Only positive W values make sense here..

w-24=0

w=24 in

So..

L=3+24

3 0
3 years ago
Jerome burns 4 cal/min walking and 10 cal/min running. He walks between 10 and 20 min each day and runs between 30 and 45 min ea
erik [133]

Answer:

20 minutes should spend on walking and 30 minutes on running.

Step-by-step explanation:

Let x represents the minutes spent on walking and y represents the minutes spent on running,

∵ He burns 4 cal/min walking and 10 cal/min running,

So, the total calories burnt,

Z = 4x + 10y

Which has to be maximised.

Now, he walks between 10 and 20 min each day,

i.e. 10 < x < 20,

Also, he runs between 30 and 45 min each day,

i.e. 30 <  y < 45,

By graphing 10 < x < 20 and 30 <  y < 45,

We obtained the vertices of feasible region,

(10, 45), (20, 45), (10, 30) and (20, 30)

At (10, 45),

Z = 4(10) + 10(45) = 40 + 450 = 490,

At (20, 45),

Z = 4(20) + 10(45) = 80 + 450 = 530,

At (10, 30),

Z = 4(10) + 10(30) = 40 + 300 = 340,

At (20, 30)

Z = 4(20) + 10(30) = 80 + 300 = 380

Hence, maximum calories is 530 when 20 minutes spent on walking and 30 minutes spent on running.

5 0
3 years ago
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