Answer:
A two-digit number can be written as:
a*10 + b*1
Where a and b are single-digit numbers, and a ≠ 0.
We know that:
"The sum of a two-digit number and the number obtained by interchanging the digits is 132."
then:
a*10 + b*1 + (b*10 + a*1) = 132
And we also know that the digits differ by 2.
then:
a = b + 2
or
a = b - 2
So let's solve this:
We start with the equation:
a*10 + b*1 + (b*10 + a*1) = 132
(a*10 + a) + (b*10 + b) = 132
a*11 + b*11 = 132
(a + b)*11 = 132
(a + b) = 132/11 = 12
Then:
a + b = 12
And remember that:
a = b + 2
or
a = b - 2
Then if we select the first one, we get:
a + b = 12
(b + 2) + b = 12
2*b + 2 = 12
2*b = 12 -2 = 10
b = 10/2 = 5
b = 5
then a = b + 2= 5 + 2 = 7
The number is 75.
And if we selected:
a = b - 2, we would get the number 57.
Both are valid solutions because we are changing the order of the digits, so is the same:
75 + 57
than
57 + 75.
It depends on how deep the submarine is... do you happen to know that?
Answer:
I think is number 1
Step-by-step explanation:
You can use the ordered pairs to describe the translation that took place.
If you choose any vertex, you can use that to describe the translation that occurred with all vertices.
I'll look at N. Vertex N moved to the right 5 and up 7.
You can use the beginning and ending ordered pairs to see these distances.
Start: (-1, -1)
End: (4, 6)
-1 to 4 is 5 units
-1 to 6 is 7 units
Answer:
Option A - 10
Step-by-step explanation:
Given : There are 3 red chips and 2 blue chips. If they form a certain color pattern when arranged in a row, for example RBRRB.
To find : How many color patterns are possible?
Solution :
Total number of chips = 5
So, 5 chips can be arranged in 5! ways.
There are 3 red chips and 2 blue chips.
So, choosing 3 red chips in 3! ways
and choosing 2 blue chips in 2! ways.
As changing the places of similar chip will not create new pattern.
The total pattern is given by,
Therefore, color patterns are possible are 10.
Option A is correct.
