Answer:

Step-by-step explanation:
To rid the denominators, multiply both sides by
.
We get:

Simplifying, we have:

Solving, we get:

Therefore, the solution with the greatest value is 
Answer:
AD = 13
Step-by-step explanation:
Area of trapezoid ABCD

5 and 5/10s sounds like 5.5 so I'd do 5.5+0.02=5.52
Answer:
anything raised to the power of zero= 1
(1+1/4^½)²
(1 + 1/2)²
(3/2)²
9/4
=2.25
1000 grams = 1 kilograms.....
the average mass of cat is 5000 grams, so if you convert this into KG then the answer would be 5 kg because if 1000*5 = 5000 which equals to 5 kg.....hope this helps :)