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ycow [4]
3 years ago
14

Joe is trying to soup up his dragster. He knows that the time needed for the car to go from 0 to 100 miles per hour varies inver

sely with the car's horsepower. At 200 horsepower, the car can go from 0 to 100 mph in 10 seconds. How long should the car take if he can increase the horsepower to 250 hp?
Mathematics
1 answer:
inysia [295]3 years ago
3 0
8 seconds

The hardest part of this is setting up the equation -- the calculations are pretty easy.

You're told that the time (needed to go from 0 to 100 MPH) is inversely proportional to the horsepower:  what this means is that as horsepower gets larger, time gets smaller. This makes sense since the more horsepower you have, the less time it will take you to get to 100 MPH

You can think of this as:

200 HP = 10 seconds
250 HP = x seconds

You set the equation up as:

250 HP / 200 HP = 10 sec / x sec

Now, just cross multiply and solve:

250 / 200 = 10 / x
250x = (200 x 10)
250x = 2000
x = 2000 / 250
x = 8

So, as you increase the horsepower from 200 to 250, the time decreases from 10 seconds to 8 seconds.

Hope this helps!

Good luck.
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An alarming number of U.S. adults are either overweight or obese. The distinction between overweight and obese is made on the ba
madreJ [45]

Answer:

(A) The probability that a randomly selected adult is either overweight or obese is 0.688.

(B) The probability that a randomly selected adult is neither overweight nor obese is 0.312.

(C) The events "overweight" and "obese" exhaustive.

(D) The events "overweight" and "obese" mutually exclusive.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = a person is overweight

<em>Y</em> = a person is obese.

The information provided is:

A person is overweight if they have BMI 25 or more but below 30.

A person is obese if they have BMI 30 or more.

P (X) = 0.331

P (Y) = 0.357

(A)

The events of a person being overweight or obese cannot occur together.

Since if a person is overweight they have (25 ≤ BMI < 30) and if they are obese they have BMI ≥ 30.

So, P (X ∩ Y) = 0.

Compute the probability that a randomly selected adult is either overweight or obese as follows:

P(X\cup Y)=P(X)+P(Y)-P(X\cap Y)\\=0.331+0.357-0\\=0.688

Thus, the probability that a randomly selected adult is either overweight or obese is 0.688.

(B)

Commute the probability that a randomly selected adult is neither overweight nor obese as follows:

P(X^{c}\cup Y^{c})=1-P(X\cup Y)\\=1-0.688\\=0.312

Thus, the probability that a randomly selected adult is neither overweight nor obese is 0.312.

(C)

If two events cannot occur together, but they form a sample space when combined are known as exhaustive events.

For example, flip of coin. On a flip of a coin, the flip turns as either Heads or Tails but never both. But together the event of getting a Heads and Tails form a sample space of a single flip of a coin.

In this case also, together the event of a person being overweight or obese forms a sample space of people who are heavier in general.

Thus, the events "overweight" and "obese" exhaustive.

(D)

Mutually exclusive events are those events that cannot occur at the same time.

The events of a person being overweight and obese are mutually exclusive.

5 0
2 years ago
a trucking company shipped a total 151,375 boxes of fruit across the company. How many thousands of boxes of fruit were shipped?
Ostrovityanka [42]

Answer:

The trucking company shipped a total of 151 thousands of boxes of fruits

Step-by-step explanation:

Total boxes of fruits shipped= 151,375

How many thousands of boxes of fruit were shipped?

To find the thousands of boxes of fruits shipped, divide the total number of boxes of fruits shipped by 1000

That is

151,375 / 1000

= 151.375

Therefore, the trucking company shipped a total of 151 thousands of boxes of fruits

151,375

Place value of each figure from right to left

5= one

7= tens

3= hundred

1= thousand

5= ten thousand

1= hundred thousand

4 0
3 years ago
Christian wants to make an A in his class. There are 5 exams this year, and he has taken 4 of them. His grades were 84, 88, 95,
ioda

Answer:

last test grade=x     x ≥ 79 so 79%

Step-by-step explanation:

(84/5)+(88/5)+(95/5)+(104/5)+(x/5) ≥ 90

Simplify: (371/5)+(x/5) ≥ 90

Subtract (371/5) from both sides

Then you have (x/5) ≥ (79/5)

Then multiply both sides by 5 and you have x ≥ 79

P.S. If it was helpful please consider giving me brainliest. =)

3 0
3 years ago
Juma earns $12.50 for each newspaper subscription he sells. He also earns a $50 base salary each week. If he wants to earn $400
garik1379 [7]

Answer: 400=12.50x+50

400-50=12.50x

350=12.50x

350÷12.50=x

28=x

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
Solve the inequality 2(4x+1)&lt;3(2x-3)
Ostrovityanka [42]

Answer:

X<-11/2

Step-by-step explanation:

Hope I helped:)

5 0
2 years ago
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