Following actions could you most likely advise the client taking to strengthen the security of their wireless network-
- Change the default SSID to anything different.
- Turn off SSID broadcasting.
<h3>Explain the term wireless network security?</h3>
- Designing, putting into practice, and ensuring security on such a wireless computer network are all parts of wireless network security.
- A wireless computer network is further protected by this subset of network security.
- Wireless security is another name for wireless network security.
For the stated question-
- Disabling SSID broadcast and changing the network name are advised.
- By disabling SSID, the network name won't be displayed on devices looking for a network can connect to, and so by changing the name, it will be impossible for anyone who already knows the old name to connect.
- Both of which significantly boost security.
To know more about the wireless network security, here
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<span>Missing route on the default gateway router.</span>
Answer:
Hardware and software are the mandatory parts
anyway keyword mouse monitor are not hardware parts of computer
Answer:
it is not seeing full. please give full
Answer:
- If a group of 9 kids have won a total of 100 trophies, then at least one of the 9 kids has won at least 12 trophies.
- If a person buys at least 400 cups of coffee in a year, then there is at least one day in which the person has bought at least two cups of coffee.
- The average of three real numbers is greater than or equal to at least one of the numbers.
Explanation:
1)
Suppose that each kid has less than 12 trophies
Total trophies = 100
Maximum trophies won by one kid = 11
total kids = 9
total number of trophies = 9 * 11 = 99 which contradicts the fact the total number of trophies are 100
2)
Suppose that person has less than 2 cups of coffee a day
Total cups of coffee = 400
he has bought at least one cup of coffee each day
which means
total number of cups of coffee = 1* 366 = 366 which contradicts the fact the person buys at least 400 cups of coffee in a year
3)
Average of three number = (a+ b+ c)/3
suppose that there are real numbers a, b, and c such that all three numbers are less than the average of the three numbers.
Let m be the average (a+b+c
)/3 = m. Then our assumption states that (a < m) and (b < m) and (c < m). By adding all the inequalities we get a + b + c < 3m. But m is defined to be (a+b+c)
/3 , so a + b + c = 3m. But now we have that 3m = a + b + c < 3m. So 3m < 3m which is an obvious contradiction. Thus our claim is true