Question

Declare a character variable letterStart. Write a statement to read a letter from the user into letterStart, followed by statements that output that letter and the next letter in the alphabet. End with a newline. Hint: A letter is stored as its ASCII number, so adding 1 yields the next letter. Sample output assuming the user enters 'd': de

Answer 1

Answer:

public class ANot {

   public static void main(String[] args) {

       System.out.println("Enter a char");

       Scanner in = new Scanner(System.in);

       char letterStart = in.next().charAt(0);

       char nextCha = (char)(letterStart+1);

       System.out.print(letterStart);

       System.out.println(nextCha);

   }

}

Explanation:

The main logic here is understanding that characters in Java are stored as ASCII numbers and as such some mathematic operations can be carried out on them. So we add 1 to the value of the entered character to get the character next to it, the opposite is also possible (Subtracting 1 to get the value before it)

Note also that in reading a character using the scanner class Java does not support the nextChar like it does for other primitive data types so we use the method charAt(). To obtain the character at a particular index.