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ivolga24 [154]
3 years ago
13

How do you evaluate 2d-5 to get your answer

Mathematics
2 answers:
alex41 [277]3 years ago
6 0

Answer:

You have to find out what d is

Step-by-step explanation:

1.) find out what d is

2.) do 2 x d

3.) subtract 5 from 2 x d

Law Incorporation [45]3 years ago
4 0
AhhhhhhhhooooooOoOooOO

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Find the cdf F(x) associated with each of the following probability density functions. Sketch the graphs of f(x) and F(x).
wolverine [178]

Answer:

See steps below

Step-by-step explanation:

a)

\bf f(x)=3(1-x)^2\;(0

\bf F(x)=\int_{0}^{x}f(t)dt=\int_{0}^{x}3(1-t)^2dt=3\int_{0}^{x}(1-t)^2=1-(1-x)^3

The cdf associated with f is

\bf \boxed{F(x)=1-(1-x)^3} for 0<x<1

<h3>See picture 1 </h3>

The median is a point x such that

F(x) = ½

so, the median is

\bf 1-(1-x)^3=1/2\rightarrow (1-x)^3=1/2\rightarrow \boxed{x=1-\sqrt[3]{2}}

The 25th percentile equals the 1st quartile and is a point x such

F(x) = ¼

and the 25th percentile is

\bf 1-(1-x)^3=1/4\rightarrow (1-x)^3=3/4\rightarrow \boxed{x=1-\sqrt[3]{3/4}}

b)

\bf f(x)=\frac{1}{x^2}\;(1

\bf F(x)=\int_{1}^{x}f(t)dt=\int_{1}^{x}\frac{dt}{t^2}=1-\frac{1}{x}

The cdf associated with f is

\bf \boxed{F(x)=1-\frac{1}{x}} for x>1

<h3>See picture 2 </h3>

The median is

\bf 1-\frac{1}{x}=\frac{1}{2}\rightarrow \boxed{x=2}

The 25th percentile is  

\bf 1-\frac{1}{x}=\frac{1}{4}\rightarrow \boxed{x=4/3}

c)

f(x) = 1/3 for 0<x<1 or 2<x<4

\bf F(x)=\int_{0}^{x}\frac{dt}{3}=\frac{x}{3}\;(0

\bf F(x)=\frac{1}{3}+\int_{2}^{x}\frac{dt}{3}=\frac{1}{3}+\frac{x-2}{3}=\frac{x-1}{3}\;(2

The cdf associated with f is

\bf F(x)=\frac{x}{3} for 0<x<1

\bf F(x)=\frac{x-1}{3} for 2<x<4

<h3>See picture 3 </h3>

The median is

\bf \frac{x-1}{3}=1/2\rightarrow x=1+3/2\rightarrow \boxed{x=5/2}

The 25th percentile is  

\bf \frac{x}{3}=1/4\rightarrow \boxed{x=3/4}

4 0
4 years ago
Fred is making a fruit salad the ratio of cups of peaches to cups of cherries is 2:3 how many cups of peaches will fred need to
mart [117]
2c : 3c = 60

5c = 60

c = 12

Fred will need 24 cups of peaches to make 60 cups of fruit salad.
8 0
3 years ago
What is the interquartile for this set of data? 11,19,35,42,60,72,80,85,88
exis [7]

Answer:

55.5

Step-by-step explanation:

find the median - in this case it's 60

then group the upper and lower halves of the data:

(11, 19, 35, 42) 60 (72, 80, 85, 88)

now we find the medians of those sets:

35 + 19/2 = 54/2 =27

80 + 85/2 = 165/2 = 82.5

then subtract those two medians to find the interquartile:

82.5 - 27 = 55.5

4 0
3 years ago
8. Given that DAB and DCB are right angles and BDC = 55°, what is m CAD?
Artyom0805 [142]

Answer:

d

Step-by-step explanation:

d

5 0
3 years ago
25 points :)))))))))
kiruha [24]
Answer:

s = 15

Step-by-step explanation:

We know that a straight line measures 180°

so… in order to find the value of s add the two angles with a sum of 180 and then solve for s

(9s + 8)° + 37° = 180°

Combine like terms

9s + 45 = 180

Subtract 45 from both sides

9s = 135

Solve for s

s = 135/9

s = 15







8 0
3 years ago
Read 2 more answers
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