Answer: hello your question is vague hence i will provide a more general answer
Area of a right angled triangle = 1/2 * b * h
Step-by-step explanation:
For a right- angled triangle; the sum of squares of the opposite and adjacent sides = square of the longest side ( i.e. hypothenuse )
hence the Area of a right angled triangle = 1/2 * b * h
where : b = adjacent , h = opposite side
Depends on which way you look at it. 100 tickets at 5 is 500 total. but if your payout is 300 then divide that by 100 which is 3. So the average value of a ticket is 3 while the other 200 goes to whatever.
The percent increase is 18.18 repeating
Triangle-A is not "unique".
All of its angles are equal (60° each), and all of its sides
have the same length, but that length can be anything ...
1 millimeter, 1 light-year ... anything.
Each of the other choices can only be 1 triangle.
For each one, we can find the size of every angle,
and we can also find the length of every side.
<span>For the
presented problem, the solution would be</span><span> </span><span>v</span><span>(0)=0</span><span>v(0)=0</span><span> is</span><span>v</span><span>(</span><span>t</span><span>)−</span><span>mgb</span><span>=</span><span>e</span><span>−</span><span>b</span><span>/</span><span>m</span><span>⋅</span><span>t</span><span>(</span><span>v</span><span>0</span><span>−</span><span>mgb</span><span>)</span><span>⟺</span><span>v</span><span>(</span><span>t</span><span>)=</span><span>mgb</span><span>(</span><span>1−</span><span>e</span><span>−</span><span>b</span><span>/</span><span>m</span><span>⋅</span><span>t</span><span>)</span><span>≈</span><span>g</span><span>⋅</span><span>t</span><span>−</span><span>gb</span><span>2</span><span>m</span><span>⋅</span><span>t</span><span>2</span><span>,
with the following given, </span><span>
m</span><span>=180[lb]=81.6[kg]</span><span> </span>
<span>g</span><span>=9.81[m/s</span><span>2</span><span>]</span><span />
<span>b</span><span>=0.75[kg</span><span>⋅</span><span>m/s</span><span>2</span><span>⋅</span><span>s/ft]=0.2286[kg/s]</span><span />
<span>The solution that the
friction provides is </span><span>v</span><span>(</span><span>t</span><span>)=3501.7[m/s]</span><span>⋅</span><span>(</span><span>1−</span><span>e</span><span>−0.00280[1/s]</span><span>⋅</span><span>t</span><span>), where I get </span><span><span>96.69</span></span><span /><span><span><span><span>[</span></span><span /><span><span>m</span></span><span /><span><span><span><span>/</span></span></span></span></span><span><span><span>s</span></span><span /><span><span>]</span></span></span><span>=</span></span><span /><span><span>317.2</span></span><span /><span><span><span><span>[</span></span><span /><span><span>f</span><span>t</span></span><span /><span><span><span><span>/</span></span></span></span></span><span><span><span>s</span></span><span /><span><span>]</span></span></span></span><span><span /></span><span>. I
am hoping that this answer has satisfied your query about this specific
question.<span /></span>