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Harman [31]
3 years ago
15

The area of a rectangle is 36 square meters. If the length of the rectangle is 3, what is the width?

Mathematics
1 answer:
bekas [8.4K]3 years ago
8 0
Area = length x width

So, 36/3 = 12

Width is 12
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A student took two national standardized tests while applying for college. On the first test,
kvv77 [185]

Answer:

a

Step-by-step explanation:

4 0
2 years ago
A store brought 9 cases of light bulbs in May and 8 cases in June. There are 48 light bulbs in a case. How many light bulbs did
UkoKoshka [18]
So the store bought 9 cases of lightbulbs and in a case, there are 48.
9 * 48 = the number of lightbulbs in the nine cases. 432 is the number of light bulbs in the 9 cases they bought in May. So then let's move on to the cases they bought in June. Do the same thing 8 * 48 is 384. So then add the two amounts together and then you will get 816 which will be your answer. I hope this helps!
5 0
3 years ago
Read 2 more answers
Consider the line x+5y=6
Tems11 [23]

Answer:

x + 5y = 6 is perpendicular to y = 5x + \frac{6}{5} and parallel to y = -\frac{1}{5}x + 2\\

Step-by-step explanation:

First, convert the equation to standard form so that y is isolated.

x + 5y = 6 --> x - 6 = -5y (divide both sides by -5) --> y = -\frac{1}{5}x + \frac{6}{5}

A perpendicular line will have a slope that is the opposite reciprocal of the original slope (meaning you flip the numerator and denominator then make it negative).

-\frac{1}{5} is perpendicular to -(\frac{-5}{1} ) which simplifies to 5.

A parallel line will have the same slope, but the y-intercept will be different. It can be pretty much any number as long as the original slope is used in the new equation.

y = -\frac{1}{5}x + \frac{6}{5}\\ is parallel to y = -\frac{1}{5}x + 2\\ just like y = -\frac{1}{5}x - \frac{100}{23}.

6 0
2 years ago
Which angle pairs are supplementary? Check all that apply. ∠1 and ∠2 ∠4 and ∠3 ∠4 and ∠5 ∠7 and ∠5 ∠3 and ∠6.
Alla [95]

Answer:

∠4 and ∠3

∠4 and ∠5

∠3 and ∠6.

Step-by-step explanation

Find the diagram attached

First you must note that the sum of two supplementary angles is 180°

Also, since the sum of angle on a straight line is 180°, the angles that are supplementary must lie on the same straight line.

Based on the diagram, the pair of angles that lies on the same straight line are ∠4 and ∠3, ∠4 and ∠5 and ∠3 and ∠6. If that is the case, hence this angles are supplementary.

6 0
2 years ago
write the equation of a line that passes through the points (5, -7) and is perpendicular to the line -2x + 6y = -4
VashaNatasha [74]

Answer:

y= -3x + 8

Step-by-step explanation:

Put -2x + 6y = -4 into slope-interceltp form

Take the negative reciprocal of the slope.

Use this reciprocal in point-slope form

and you have,

= y= -3x + 8

<em>(EDITED)</em> Steps:

2x+6y = -4

6y=2x - 4

y= 1/3x + 2/3

if two lines are perpendicular,

m1 * m2 + -1

1/3 * m2 = -1

m2 = -3

the line perpendicular to this line is

y = -3x + k ; k ∈ R

the line passes through the point (5,-7)

so,

-7 = -3. (5) +k

-7 = -15 + k

k = 8

∴the equation of a line that passes through the point (5,-7) and is perpendicular to the line -2x+6y=-4 is

y= -3x + 8

Hope this helps, have a nice day/night! :D

6 0
2 years ago
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