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3 years ago

Determined to find the slope(1 7K), and (-3,5K)

Mathematics

1 answer:

Helga [31]3 years ago

8 0

Answer: $\dfrac{K}{2}$ .

Step-by-step explanation:

As we know ,

The slope of a line that passes through $(x_1,y_1)$ and $(x_2,y_2)$ is given by :

$\dfrac{y_2-y_1}{x_2-x_1}$

The slope of a line that passes through (1 , 7K), and (-3,5K) =

$\dfrac{5K-7K}{-3-1}\\\\=\dfrac{-2K}{-4}\\\\=\dfrac{K}{2}$

Hence, the slope of the given line is $\dfrac{K}{2}$ .

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$\hat{p}\pm z^*\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

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3 years ago

Determined to find the slope(1 7K), and (-3,5K)​

Determined to find the slope(1 7K), and (-3,5K)