9 - x < 8 => -x < 8 - 9 => -x < -1 => x > 1
9 - x > 3 => -x > 3 -9 => -x > -6 => x < 6
So the number is between 1 and 6, notation 1 < x < 6
Answer:

Step-by-step explanation:
Given: 
To solve this equation, we need to isolate
on one side of the equation algebraically. I see that we have like terms, but they are on opposite sides of the equal sign. Let's add
to both sides.

To isolate x, divide both sides by 7.

To simplify this, you would have to turn b^-2 into a positive exponent.
To do this, we have to flip b^-2, which would get rid of the negate from the exponent: -2
3a^4 b^-2 c^3 / b^-2
Then we get the answer:
3a^4 c^3
------------
b^-2
I have a picture to clarify!
I hope this helped, let me know if you don't understand! ^.^
One expression could be three x to the power of two. Let me know if that's right :)