$\frac{4}{y^{2}-9 } + \frac{5}{y+3} = \frac{4}{(y-3)(y+3) } + \frac{5}{y+3}= \frac{4}{(y-3)(y+3) } + \frac{5(y-3)}{(y-3)(y+3)}=
\\ \\=\frac{4}{(y-3)(y+3) } + \frac{5y-15}{(y-3)(y+3)}= \frac{5y-11}{(y-3)(y+3)}=\frac{5y-11}{y^{2}-9}
$

8 0

3 years ago

Red and grey bricks were used to build a decorative wall. The number of red bricks and grey bricks was 5/2. There were 140 brick

ozzi

Answer:

100 red bricks

Step-by-step explanation:

Let's say red bricks is equal to 5x

Gray bricks is equal to 2x

We have an equation

2x + 5x = 140

= 7x = 140

Divide through by 7 to get the value of x

X = 140/7

X = 20

Red bricks = 5(x)

= 5(20)

= 100

Gray bricks = 2(x)

= 2(20)

= 40

Therefore in conclusion the number of red bricks is 100.

5 0

2 years ago

Help plz will give brainliest

jolli1 [7]

Answer: 5(13.5-4.5)

5(9)

=45

6 0

2 years ago

X=x property of equality

Mekhanik [1.2K]

Answer:

Reflexive Property

Step-by-step explanation:

For all real numbers x , x=x . A number equals itself

7 0

2 years ago